MisterBill2
- Joined Jan 23, 2018
- 27,679
If the 120 ohm resistor burns then there must be excessive current flowing so that THE POWER GREATLY EXCEEDS THE RATINGS. For 120 ohms the current at 12 volts will be 12v/120 ohms= 100mA=0.1 amp. So the power (= V x I) would be12v x 0.1A=1.2 watts. That should not damage a 2 watt resistor.
But it seems that the 22 ohm resistor is causing the base drive of the pass transistors to be excessive,Thus the regulator is not in control at all, and so the output voltage is much greater than twelve volts. That looks like the problem.
But it seems that the 22 ohm resistor is causing the base drive of the pass transistors to be excessive,Thus the regulator is not in control at all, and so the output voltage is much greater than twelve volts. That looks like the problem.
