Oh ok.The output is (Va - Vb) x amplifier gain, where Va is the non-inverting input and Vb is the inverting input.
Hence,
Vout = (0V - 3V) x gain = -Vs
Yes but I was said that input polarity doesn't matterBecause the +3 volts is going into the inverting input so it will come out reversed polarity.
Those statements are incorrect.
It is not the polarity that matters. It is the voltage difference that matters.
(+IN) - (-IN)
Yes.When I have Op Amp with positive feed back it will be saturated.
What do you mean "undetermined".And undetermined on the positive input ?
I was just curious if I can tell if the Vout equations works here.Yes.
What do you mean "undetermined".
The voltage to both inputs is always determined.
If one of the input's voltage is undetermined, than the output voltage is also undetermined.
That's because a bistable circuit has two stable states but you know it has to be in one of the two states.Because I don't know what is in positive input I know only negative input that is 4V
What negative feedback?Oh and is it possible to have positive output while having a positive voltage on negative input ? (while having negative feedback) ?
Yes we were talking about positive feedback.What negative feedback?
So far we've been talking about positive feedback.
Schmitt trigger
We have explained to you that its the differential input voltage, not the voltage on one pin that determines the output.But I was also curious about that one input doesn't determine what is the output.
Oh cool. Something like that ?Vout = -R2/R1 x (v1 - v2)
If the positive input is v1, then the output will be positive if v2 > v1.
Ok.Treat positive feedback circuit as a different case altogether.
Study negative feedback circuit alone and master it.
View attachment 272659
Vout = -Vin x R2/R1
?
by Aaron Carman
by Aaron Carman
by Duane Benson
by Duane Benson