Almost ”no”. Make sure that it doesn't lower the corner frequency of the high pass filter created by Cout and R pull-down in parallel with Rin of the next stage by an unacceptable amount.Thanks for the explanation. So does that mean with a 10K (instead of a 100K), it'd charge it faster and be less likely to hear any pop?
In terms of that same resistor, does it load down the outgoing signal at all in any adverse way (100k vs 10k)?
Make sure that the op-amp has sufficient output current to drive both R pull-down and R in in parallel.
The drop in voltage due only to the decreases resistance will be small, because of the low output resistance of an op-amp with feedback.
Your 9V battery has to supply the current through the pull-down resistor, and that may reduce the battery life.