NO, you will blow the transistors as they will turn on together and short out the supply.
You need to cross connect the Bases so that opposite transistors conduct, So top Left and Bottom Right bases , top Right and bottom Left.
ThanksNO, you will blow the transistors as they will turn on together and short out the supply.
You need to cross connect the Bases so that opposite transistors conduct, So top Left and Bottom Right bases , top Right and bottom Left.
ThanksBut this isn't a full bridge, it's a half-bridge with two transistors in parallel.
Provided that the top pair is on when the bottom pair is off, and there is sufficient dead-time to allow the IGBTs to turn off, it will work.
thanksTop MOSFETs and bottom MOSFETs must never be on at the same time.
There must be a short time when no MOSFETs are on.
Bottom MOSFETs are driven by a driver sitting on (-).
Top MOSFETs is driven by a signal that is not related to (-) but by (AC)
View attachment 221162
Top MOSFETs and bottom MOSFETs must never be on at the same time.
There must be a short time when no MOSFETs are on.
Bottom MOSFETs are driven by a driver sitting on (-).
Top MOSFETs is driven by a signal that is not related to (-) but by (AC)
View attachment 221162
Where are you measuring 220A?And can it dispense up to 220a?
That arrangement (post #1) with the coil connected by a capacitor is a common way of doing things. The coil will see ±half the supply voltage and that may be what the design expects.You need to put the Coil/Transformer between the transistors Collectors , that way it will pulse across the supply.
what about (post #6)No, this circuit ) will destroy the transistors.
Please how ?No, this circuit (post #8) will destroy the transistors.
Post #6 is correct. The signals feeding the mosfets must be 180 degrees out of phase.Please how ?
what about (post #6)
This connection is correct tooPost #6 is correct. The signals feeding the mosfets must be 180 degrees out of phase.
Whichever of the inputs is active there will be one top transistor and one bottom transistor turned on. This puts them conducting across the supply - a near short circuit.Please how ?
What about this ?AlbertHall said:
No, this circuit (post #8) will destroy the transistors.
Whichever of the inputs is active there will be one top transistor and one bottom transistor turned on. This puts them conducting across the supply - a near short circuit.
That's correct but remember the drive signals must be 180 degrees out of phase.What about this ?
Ok thanksWhen the top signal is high the bottom must be low and vice versa.
View attachment 221219
ThanksGet one of these to drive it:
https://www.onsemi.com/products/discretes-drivers/gate-drivers/fan73933
thanksThat arrangement (post #1) with the coil connected by a capacitor is a common way of doing things. The coil will see ±half the supply voltage and that may be what the design expects.
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