Thank you for the help i realized i needed a resistor to the input.

 

Now how do i change GP4 to a input pin with TRISIO = 0x02;.
thanks again for the help, also how can i learn what 0x02 is and how it associate GP0 GP1 as out and in?
thansk

 

You need a resistor in series with the LED, perhaps 470Ω, to avoid the read-modify-write problem and a pull down resistor for GP1, perhaps 10k.

 

Now how do i change GP4 to a input pin with TRISIO = 0x02;.
thanks again for the help, also how can i learn what 0x02 is and how it associate GP0 GP1 as out and in?
thansk

Consider the value in binary. 0x02 is binary 00000010. Each binary bit represents an IO pin, LSB is GP0 then going in sequence.

 

As I commented earlier (post #2), I am not sure how the compiler works. Addressing the individual pins can be a little confusing in these devices. If you want GP4 it is bit #4 in a 6-bit register. The upper two bits of the register are not read:


The hex value would be 0x10. If you want GP2 (see your post #22), then the hex value is 0x04.(see edit) I find it convenient and a little more obvious to use the binary representation, e.g., b'00010000' for GP4, when referencing GPIO pins.

EDIT: I am a victim of using binary and being half asleep. From the include file,

The default radix of the chip is hex, so GP4 = GPIO,4