What is the purpose of this circuit?

 

hi sith,
Is this homework or a college assignment?
E

 

It is someone’s effort at simulating an idea for a low-pass attenuator.
Why do you want to know?

 

hi sith,
It is a differential amplifier with a +1.5V off set on the output.
Differential Gain ~0.2
E
edit

 

The datasheet of the OP292 opamp says its minimum supply is 4.5V then it will not work it this circuit that has a 3.3V supply.

 

Differential Gain ~0.2

Looks to me like ≈0.1.
How did you get 0.2?

 

My guess is that it gives a 50Hz sinewave centred on 1.5V, from a 12V transformer, for the purpose of measuring the mains voltage using a 3.3V micro controller.
but it does need a 3.3V supply op-amp, not a OP292.