Its in the marking criteria to use a 3 to 8 decoder


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This thread was split from -- Confused on how to make a counter does what I need it to do?
Please also refer to -- I'm stuck on part A of a decoder.

 

I am also at the final part, i need to condense my 2 3-8 decoders but i cannot figure out why. My circuits look the same as Jessy1221

 

Its in the marking criteria to use a 3 to 8 decoder

What school are you guys attending? Going from 3 inputs to 8 makes the problem more difficult (IMO).

Using the gear inputs more directly makes more sense. You can't use a standard logic block to do it, but it can be implemented with AND, OR, and NOT gates.

 

Griffith Uni.
Unfortunately, this is what they want. So what would be the easiest way to go from the 2 3-8 decoders (16 outputs) and condense it into 1 led only using AND, OR and NOT gates?

 

So what would be the easiest way to go from the 2 3-8 decoders (16 outputs) and condense it into 1 led only using AND, OR and NOT gates?

This is homework, so we can only give guidance.

How would you solve any other combinational logic problem that had 6 inputs and 1 output?

EDIT: And a belated Welcome to AAC!

 

MMm, I cant seem to figure it out.

 

My difficulty is within this last section, I dont know how to connect the last part.

 

My difficulty is within this last section, I dont know how to connect the last part.

I don't think you're wiring the thing you're calling a selector correctly.

Can you post your lecture notes that covered doing something similar?

I can make the "selector thing" work, but it requires a brute force method for solving the problem.

 

Thank you for the help, i figured it out

 

Thank you for the help, i figured it out

Didn't do much, but you're welcome anyway.