Hi all,
I'm trying to drive a RFP30N06LE N-Channel MOSFET with TC4420 MOSFET Driver. The MOSFET is used to switch a [1W LED][1]. The input to the MOSFET driver is provided by the 5V from an Arduino Nano. But my circuit is not working: it seems that the VDD somehow leaks to the input of the MOSFET driver, causing it to switch on constantly. The Arduino side switch has no affect.
The VDD in the circuit is 16V, and VCC is 5V coming from an Arduino Nano. The VCC goes into the MOSFET driver's input to turn it on.
I find my LED operates best at a current draw of 291 mA. With a VDD of 16 V, I put the LED in series with a 56Ω resistor.
Here is my circuit:

And photo of the breadboard implementation (LED and resistor are off board and not shown here). Power rail runs VDD.

I'm providing the VDD with a bench power supply. I have my scope hook to 1) yellow-MOSFET driver input 2) Blue-MOSFET driver output 3) Purple-Between drain and source of the MOSFET.

You can see in this picture when I first turn on the VDD power supply at 0.5V. The yellow signal in the scope raises above the others by a little bit. I measured ~0.4V on the input pin of the driver. This does not really make sense to me because the input should be isolated from the VDD. The LED (in the foreground of the photo on the left) does not turn on.
Now when I set power supply to 4.1V. The LED turns on and it starts to draw about 0.47 A. This should not happen since I'm not giving anything to the input of the MOSFET driver (the switch between Arduino 5V and the MOSFET input is open). Yet the scope shows the voltage on the MOSFET input is as high as on its output, turning the MOSFET on. See photo below.

I suspect there are some shorting between the MOSFET input and VDD so I check with my DMM but they are open.
I'm really at a lose as to what to do. Please let me know I didn't make something clear or if you want more information. Any insight would be greatly appreciated!
I'm trying to drive a RFP30N06LE N-Channel MOSFET with TC4420 MOSFET Driver. The MOSFET is used to switch a [1W LED][1]. The input to the MOSFET driver is provided by the 5V from an Arduino Nano. But my circuit is not working: it seems that the VDD somehow leaks to the input of the MOSFET driver, causing it to switch on constantly. The Arduino side switch has no affect.
The VDD in the circuit is 16V, and VCC is 5V coming from an Arduino Nano. The VCC goes into the MOSFET driver's input to turn it on.
I find my LED operates best at a current draw of 291 mA. With a VDD of 16 V, I put the LED in series with a 56Ω resistor.
Here is my circuit:

And photo of the breadboard implementation (LED and resistor are off board and not shown here). Power rail runs VDD.

I'm providing the VDD with a bench power supply. I have my scope hook to 1) yellow-MOSFET driver input 2) Blue-MOSFET driver output 3) Purple-Between drain and source of the MOSFET.

You can see in this picture when I first turn on the VDD power supply at 0.5V. The yellow signal in the scope raises above the others by a little bit. I measured ~0.4V on the input pin of the driver. This does not really make sense to me because the input should be isolated from the VDD. The LED (in the foreground of the photo on the left) does not turn on.
Now when I set power supply to 4.1V. The LED turns on and it starts to draw about 0.47 A. This should not happen since I'm not giving anything to the input of the MOSFET driver (the switch between Arduino 5V and the MOSFET input is open). Yet the scope shows the voltage on the MOSFET input is as high as on its output, turning the MOSFET on. See photo below.

I suspect there are some shorting between the MOSFET input and VDD so I check with my DMM but they are open.
I'm really at a lose as to what to do. Please let me know I didn't make something clear or if you want more information. Any insight would be greatly appreciated!