Hi M,
Check out these video links.
E
https://www.youtube.com/results?search_query=super+posstion+theorem+examples
Check out these video links.
E
https://www.youtube.com/results?search_query=super+posstion+theorem+examples
Hi E,Hi M,
Check out these video links.
E
https://www.youtube.com/results?search_query=super+posstion+theorem+examples
Hi Ian, I have done the analysis using your method but still it does not give me the values equivalent to simulation in proteusThis is how to get an estimation of the expected result.
Does the capacitor make a significant difference? Its impedance is 10 times that of the parallel resistor at 50Hz, so assume it doesn’t.
Next, pick a few points on the AC waveform: positive peak, zero and negative peak would be good choices.
Calculate the DC voltages at the output for those voltages.
It‘s a linear circuit, so it won’t distort the sinewave, so fill in where you would expect the sinewave to be.
That gives an approximate answer, so that when you fully analyse it, you know whether your analysis might be correct.
And for capacitor, for ac analysis will it not make a difference at low frequencyHi
Hi Ian, I have done the analysis using your method but still it does not give me the values equivalent to simulation in proteus
What figures do you get for the three voltages?Hi
Hi Ian, I have done the analysis using your method but still it does not give me the values equivalent to simulation in proteus
The best way for you to learn is to give it your best attempt and show your work here. That way we can see where your trouble actually is and help get you on the right path. If we just show you everything, then you will think you have it down because it will seem to make sense at the moment, but there's a really good chance that, a week from now, you still wouldn't be able to solve a similar problem on your own.yes I know that but I am not able to solve that. Can you please tell me.
This gets at the root of the problem. You don't understand the fundamentals well enough to apply them to a circuit you haven't seen before, and so you are left trying to find the work of someone else that has solved a problem exactly like the one you are trying to solve. But doing so will leave you unable to deal any differently with the next circuit you see.Hi E,
I have gone through the links but the issue is there is not a single problem which resembles to my circuit.
Hi Ian,What figures do you get for the three voltages?
it would be 0.529Vrms and 0.748V pkhi M,
Can you solve this circuit to give the value of va?
Note: A 230Vac RMS voltage is 325Vpk.
E
View attachment 303284
Think!Hi Ian,
I have considered 498 v ac and for peak Vout across rc parallel is 1.61V, across -ve peak = -1.62V and at zero it is equal to 0.00576V
Va1 =1.75V pkHi M,
Nicely done, this sim confirms that answer.
So now try circuit #2 in this image.
E
BTW: It will help if you posted your actual calculations.
View attachment 303300View attachment 303302
I h ad 2.5V in mind but according to your circuit va1 =4.259VHi M,
I know that the original question had a 2.5Vdc source, but in my test circuit I set it at 5Vdc.
The full equations for both source voltages would be the same, except for the voltage source values.
Your equations are way off the mark, so you have an incorrect answer.
eg: your (va1-2.5v)/2k7
Why (va1-2.5v), can you explain why you think this is correct?
E
Is this correct, the Va1 would be 5.73676VSor
I h ad 2.5V in mind but according to your circuit va1 =4.259V
Also the Va1-5/2.7k, I have used nodal analysis. Is something wrong?
That looks correct for the positive peak. Now try the negative peak and zero,Is this correct, the Va1 would be 5.73676V
That looks correct for the positive peak. Now try the negative peak and zero,