If the shoe fits, wear it.Pomposity, it seems, knows no bounds.
If the shoe fits, wear it.Pomposity, it seems, knows no bounds.
My goal is to help the TS learn concepts and not just how to throw equations they don't understand at a problem. That's just helping them dig the hole they are already in deeper and deeper instead of helping them climb out. Once they are out of the hole, they will be in a position to solve the problem under the conditions of the problem statement from a standpoint of actually understanding not only why that solution is valid, but in a much better position to be able to apply it properly in less familiar situations. In all likelihood, that's the root of the current inability to solve this problem by treating it as a voltage divider -- it doesn't look exactly like the examples problems they've seen thus far with a voltage source across two resistors. Instead, they are faced with an equation that needs two resistances and the problem has four and no source to use as the V in the formula, so they are stuck, because they don't understand what the voltage divider formula is, where it comes from, what is required to make it applicable, and how to match up the parameters in the problem to the variables in the formula.The title and text in the picture posted say it's a voltage divider exercise. When I was in school, if you were told to solve a problem a certain way and you solved it using a different method, 0 credit was awarded for not following directions; even if you arrived at the correct answer.
More likely, though only the TS knows for sure, it wasn't an assumption, but rather an explicit requirement of the problem. Most problems can be solved multiple ways, but in most academic settings, the methods that are allowed on assigned problems are specified since the purpose it to develop and/or assess the student's ability to work with the particular material that the assignment is tied to.The TS might have assumed that this is a problem pertaining to a voltage divider.
Title: Understanding Basic Electronics, 1st Ed.View attachment 300875
May i know what is the voltage drop at V3 ?
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