We don't do homework. You need to show your best effort before we can offer direction.May i know what is the voltage drop at V3 ?
What is the current in R1-R4 according to Ohm's Law?
On my interpretation I see 5.6 volts across R2 and R3 looking at the meter.
5.6 volts divided by 4200 ohms = .00133 amps x R3 (3K) = 4 volts across R3.
What is the voltage across R1?
Use Ohm’s Law.
There are a couple of reasonable ways to come about it. One, indeed, is to look at it as being a voltage divider. But it's apparent that you don't understand how voltage dividers work, so even if you throw the right formulas at the problem and managed to get the right answer, your level of comprehension probably wouldn't be improved.
I don't see asking a question in the same category as "providing misleading advice", IMHO your comment was inappropriate.We don't do homework. You need to show your best effort before we can offer direction.
Members - this is a voltage divider homework assignment...
View attachment 300902
We're not supposed to do the homework (@sghioto) or give misleading advice (@Papabravo, @MrChips). Ohm's Law is not required. Current is not required. Voltage across R1 is not required.
I think the comment stems from the TS's description that this is a "voltage divider problem" and, indeed, it is not necessary to apply Ohm's Law or determine any currents in order to get the answer from that perspective. But, as I noted above, while this may be true, I don't think taking this approach is in the best interest of the TS's understanding of the fundamentals. Instead, it will lead to the all-too-common approach of trying to memorize when to throw which memorized equation at a problem, hoping to use it in such a way as to get an answer that they hope is correct.I don't see asking a question in the same category as "providing misleading advice", IMHO your comment was inappropriate.
The title and text in the picture posted say it's a voltage divider exercise. When I was in school, if you were told to solve a problem a certain way and you solved it using a different method, 0 credit was awarded for not following directions; even if you arrived at the correct answer.TS does not have to invoke an understanding of voltage dividers.
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by Jeff Child
by Jeff Child