Transistor circuit

Thread Starter

Zeeus

Joined Apr 17, 2019
481
Hi :

Trying to learn transistors... Want to calculate gain of this circuit.. understand just a little bit : book talks about input and output loading : don't understand much of it rn

Please someone throw some light

Thanks

It's not homework lol
1575814011627.png
 
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Jony130

Joined Feb 17, 2009
5,090

Thread Starter

Zeeus

Joined Apr 17, 2019
481
hi Z,
As you use LTSpice, why not create the circuit in the simulator.?
E
Hi E..sorry late reply (sleep)
Yes will use spice : just wanted to understand the theory.. The book uses spice to get Dc values
The easiest way to find the voltage gain is to use a circuit simulator. Buy because Re1 = 330kΩ and RL = 22kΩ.
This circuit will do not have any voltage gain. It is more like an attenuator.

And what you exactly do not understand?

Also, see the example here
https://electronics.stackexchange.com/questions/372891/calculating-the-transresistance-in-a-multistage-voltage-shuntshunt-shunt-feedb/372948#372948


And the name of a book is?
Hi : okay thanks... You can do not easiest way?
Thanks : the link similar problem

book : handbook of analog circuit design : Feucht
You have it
 

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Jony130

Joined Feb 17, 2009
5,090
OK. so what you want to know?

Also, I'm 100% sure that there's an error in RE value in a book, It cannot be 330kΩ. So please check this.
 

Thread Starter

Zeeus

Joined Apr 17, 2019
481
OK. so what you want to know?

Also, I'm 100% sure that there's an error in RE value in a book, It cannot be 330kΩ. So please check this.
lol yeah it's 330... you have the book? section 3.9, was not easy to follow but about trying again then read your link and see
 

ronsimpson

Joined Oct 7, 2019
344
Buy because Re1 = 330kΩ and RL = 22kΩ.
I think there is an error(s) in the book.
First: No gain?? I think 330k should be 330 ohms. Now we have gain.
Second: Bias is not right, never was. 6.1k should be 61k
In SPICE I changes the 1V signal on input to 0.5V.
Now the circuit is just strange.

Now Ve2 is at 6.8V or about 1/2 of the 12V supply. That is good.
I think "Vo" is the output not Ve2. Also strange.
With a 0.5V signal in Vin we get Ve2=about 4V and VO=3V peak.

If I was making this amplifier: (note 0.33 ohms could be 0)
1575825947352.png
 

Thread Starter

Zeeus

Joined Apr 17, 2019
481
wow thanks people..Almost thought was on "ignore list"

@ronsimpson 1 like for you : but did you notice there is distortion with your changes?

How did you get dc value? wait though : want to read again and try...will ask later
 
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Jony130

Joined Feb 17, 2009
5,090
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Thread Starter

Zeeus

Joined Apr 17, 2019
481
No, I don't have this book. But from what I see on your photo on the left sit there is a spice netlist.
Can you show it?

And here you have some examples:
https://forum.allaboutcircuits.com/threads/schematic-analysis-for-voltage-drops.85763/page-3#post-616893



But I assume that you know how to calculate the gain of a multistage amplifier?
lol..You recommend book you do not have : anyways, nice book : thanks..just 3.9 hard to follow (hard is good?)

Yes think can calculate...reading again : have received light

IMG_0167.JPG
 

Jony130

Joined Feb 17, 2009
5,090
lol..You recommend book you do not have
When and where I recommend buying this book?

Yes think can calculate...reading again
Quick test:

The voltage gain if this amplifier is?
untitled.PNG



As for your circuit from the netlist, I see that RE has a value of 330Ω and that the Vcc value is not equal to +12V by Vcc = +5V instead.
also, the BJT current gain is β = 99. Therefore the correct circuit should look like this:

ua.PNG

First, notice that this circuit can be treated as an opamp based inverting amplifier with the gain RF/RB but because we have only one CE stage that provides a voltage gain (RC/RE ≈ 66 V/V) the overall voltage gain will be less than 10V/V. Also, the voltage divider at Q2 emitter will reduce the gain further (3.9/4.9 ≈ 0.79). So, the ballpark figure of a gain is Av ≈ 66/(1 + 66*1/10)*0.79 ≈ 6.8 V/V
 

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Thread Starter

Zeeus

Joined Apr 17, 2019
481
Quick test:

The voltage gain if this amplifier is?
View attachment 194082
lol thanks...doing..less 10mins maybe
will assume U is 12

Maybe wrong...about 257? oh wait..forgot Rl..so about 51...257/5

yh?

"First, notice that this circuit can be treated as an opamp based inverting amplifier" Yes this guideline for me
 
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Thread Starter

Zeeus

Joined Apr 17, 2019
481
Why 16.2? Can you show me the calculations?
hmmm...why not? okay
want to ask : is there a thread on AAC about Latex

oh and -16.2 meant to say

Think this wrong...

Rb is 24k||430k

\[ a = β/ (β+1) \]

Vi : input voltage Ie = emitter current

\[ Ie (Re + Rb/ (β + 1)) = Vi \]

\[ Vo = -a*Ie * 20k \]

from this then found \[ Vo/Vi \]
Mistake?
 
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Thread Starter

Zeeus

Joined Apr 17, 2019
481
Latex works
View attachment 194091





\[ I_L = \frac{V_1}{R_1} \]
Is the gain correct? if wrong : think can do another calculation\[ x/y + c = 4 \]

"When and where I recommend buying this book?"
To answer this : Bordodynov posted a circuit with diff amp input : there was a capacitor placed between both emitters
DickCappels enquired about the circuit and you posted the book with the circuit. Assumed you had the book so got it (you can give me refund? : joke)
 
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