Synchronous buck converter problem

Ian0

Joined Aug 7, 2020
13,132
If the inductor current is exhausted, the switching node will no longer be negative and will track the output voltage (via the inductor. However, if the lower switch is still on, it will start discharging the output capacitor through the inductor.
The current in off state can only be sourced by stored magnetic energy in the inductor. Once exhausted, the load gets fed by the output capacitor. To summarize- the Buck input current is discontinuous. During on time if feed the load via the inductor (while storing there energy), during off time it stops (the load is fed by the inductor and output cap. The Buck output current is continuous (either from the input or from the inductor and cap). The Boost topology has it other way around - continuous input current, choppy output current. This makes the Buck an input power quality liability - the choppy input current creates choppy voltage drops in the input loop-affecting the input power source.
The buck OUTPUT current is NEVER discontinuous in a synchronous converter.
Let's assume that the input is 12V and the output is 6V.
The lower FET is on. The voltage across the inductor is -6V. The current in the inductor therefore reduces by dI/dt=V/L.
But what happens when the inductor current reaches zero?
The lower FET is STILL on. The voltage across the inductor is still -6V. The current in the inductor therefore continues to become more negative. Current from the output capacitor flows though the inductor to the negative supply, and will continue to do so until the lower FET switches off.
 

Plamen

Joined Mar 29, 2015
111
The buck OUTPUT current is NEVER discontinuous in a synchronous converter.
Let's assume that the input is 12V and the output is 6V.
The lower FET is on. The voltage across the inductor is -6V. The current in the inductor therefore reduces by dI/dt=V/L.
But what happens when the inductor current reaches zero?
The lower FET is STILL on. The voltage across the inductor is still -6V. The current in the inductor therefore continues to become more negative. Current from the output capacitor flows though the inductor to the negative supply, and will continue to do so until the lower FET switches off.
During off state fly-wheeling, the switching node voltage (in respect of GND) is slightly negative.
Once the inductor current is exhausted, the switching node gets pulled by the output voltage via the inductor .
So the switching node waveform shows 3 states ON (Vin), OFF (slightly negative), OFF Vsw=Vout.
If the lower switch is kept on throughout the OFF state, it will discharge the output cap.
Therefore the lower switch control in synchronous Buck is more complicated.
We need to pump energy to the output, not drain it.
 

Ian0

Joined Aug 7, 2020
13,132
During off state fly-wheeling, the switching node voltage (in respect of GND) is slightly negative.
Once the inductor current is exhausted, the switching node gets pulled by the output voltage via the inductor .
So the switching node waveform shows 3 states ON (Vin), OFF (slightly negative), OFF Vsw=Vout.
If the lower switch is kept on throughout the OFF state, it will discharge the output cap.
Therefore the lower switch control in synchronous Buck is more complicated.
We need to pump energy to the output, not drain it.
There are cleverer buck regulator controllers which switch off the lower FET in order to preserve mono-directional current flow in the inductor, because it reduces losses, but then operation is no longer synchronous.
 

Plamen

Joined Mar 29, 2015
111
There are cleverer buck regulator controllers which switch off the lower FET in order to preserve mono-directional current flow in the inductor, because it reduces losses, but then operation is no longer synchronous.
Тhe efficiency benefit from synchronous is notable at low input voltages i.e. most synchronous controllers are low voltage.
The idea of bypassing a diode with a MOSFET saves a diode voltage drop... and only while it conducts.
(at light load the diode is conducting briefly). Synchronous controllers also do not tolerate back-feeding i.e. applying external voltage to the output (useful in debugging). I bought a synchronous Buck module from Ali (based on MAX745)...and converted it to SEPIC so it cap produce a voltage, not only lower than the input, but also equal or higher.
 
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