hmm interesting am i close to correct in thinking this is overlaying two consecutive square waves to control duty cycle?
i thought about that previously.
hmm interesting am i close to correct in thinking this is overlaying two consecutive square waves to control duty cycle?
LTspice is free at :hey thanks greatly for this - and for taking the time to share - i don't presently have LTspice but am sure i can acquire it.
thanks for the higher res image - i'll look it over to see what else i can learn here.
regards.
No, sorry...hmm interesting am i close to correct in thinking this is overlaying two consecutive square waves to control duty cycle?
i thought about that previously.
Thanks for this explanation and the link to the software !No, sorry...
What happens is that the AC out of the 24 volt winding is full-wave rectified, attenuated by the voltage divider R1R2, and sent to U1, a voltage comparator used as a zero-crossing detector. U1 produces a short, low-going pulse, ZC-, which straddles the low-going peaks of the full-wave rectified AC waveform, ZCAC.
ZC- is used to trigger U2, a 555 one-shot which generates a positive pulse with a period corresponding to
t = 1.1R7C3.
When U2 times out it generates a negative edge which is differentiated by C3 and used to trigger U3. U3 is used to generate a short positive pulse which is used to latch the RS latch U4B U4C,and turn on M1 for the remainder of the DC half-cycle in play at that time, and when the half-cycle decays to zero volts, U4A will reset the latch and turn M1 OFF.
Note that the longer U2 stays ON, the shorter will be the time 33DC will be allowed to pump current through R10. That is, the shorter the output pulse from U2, the more power R10 (your soldering iron) will dissipate. Also note the signal into R10 is full-wave rectified AC and the power dissipated by M1 will be much less than that dissipated by a TRIAC.
I've not shown it, but R7 might best be replaced by a pot sufficiently padded to make sure that U2's output pulse is always shorter than 10 milliseconds if the AC mains are 50Hz.
Zoom in on a cycle or two of the plot and you can easily see the sequential nature of the machine.
indeed it looks like a step up in functionality from the dimmer switch but also simple enough to be reliable - in keeping with your tag i guess : )@K.e The reason I like the method in #27 is the simplicity.
I tried a few methods before settling on this.
Max.
ah yes of course - thanks Max:Capacitors together with inductors are termed filters and generally form a filter of some kind and can effect a phase shift, depending on how they are used, (see LC tuned circuits) one of the simplest way to invert a signal without loss is generally a Mosfet, transistor or logic IC.
Max.
indeed will do .You need to show a drawing of your circuit.
Max.
indeed will do .
Here is the circuit so far this doesn't include the 555 but it is only when i connect the inverted section to Pin 2 does the Trans overheat and fry.You need to show a drawing of your circuit.
Max.
Ok thanks that will help me - as to your question that is a good question ha ha.You have a transistor connected to two supplies that don't have a common reference point.
What is the reason for two bridges?
Max.
thinking more about it -:You have a transistor connected to two supplies that don't have a common reference point.
What is the reason for two bridges?
Max.
but you use an opto correct? and that provides the zero cross ref.The Vcc is presumed to be designer/customer supplied from an individual source, this makes the logic circuit isolated.
If you use this method the input and output have to be isolated.
In my case I power the 5v logic for the micro from the same source as the bridge.
Max.
lets say i'm just using a 9v battery to run the 555, then the problem becomes where and how to get the pulse to switch on the zero cross. which is why any of it functions by controlling the 'phase cut 'of the AC though the duty cycle of the 555.The Vcc is presumed to be designer/customer supplied from an individual source, this makes the logic circuit isolated.
If you use this method the input and output have to be isolated.
In my case I power the 5v logic for the micro from the same source as the bridge.
Max.
No, if you look at the circuit I posted earlier the only opto is the Triac driver, not the detection. I am using a 5v zener to regulate the Pic supply.but you use an opto correct? and that provides the zero cross ref.
ok you are talking about 'D4' in your image? - I can't see much else on there the Res is too low but that helps, for example on my DL image it looks like there are 2 D4's.No, if you look at the circuit I posted earlier the only opto is the Triac driver, not the detection. I am using a 5v zener to regulate the Pic supply.
I am detecting the 720us pulse before the zener.
If you use a 9v battery for the logic then it would be advised to use the set up as in the AN 3006.
Max.