Yes. As I said in post #213,
"In the Test position only, S1b connects the cathodes of diodes D1,D2 to ground. This allows base current to flow in both Q1 and Q2 via R4 and R6, thus switching on Q1 and Q2 irrespective of the state of both the dark sensor and the PIR."

 

yes you did, my apologies. I went to look for the post to answer your question about the clock and I must have gotten side tracked. which is good in a way because it made me have to look at it very closely to determine how it works. and the light did come on!!!

in regards to the clock. would it require (4) individual clock circuits if I wanted to change the wait time between the 10 second pulse. like have (4) settings, 15 min, 30 min, 45, and the original hour?

 

OK, I am going to "attempt" to use the software to lay this out. I am fairly SURE that I will need to change the component numbers on the clock circuit because it will/would be confusing to the program to have (2) C1, (2) R1,234 etc???? correct?

 

in regards to the clock. would it require (4) individual clock circuits if I wanted to change the wait time between the 10 second pulse. like have (4) settings, 15 min, 30 min, 45, and the original hour?

No. The wait time is determined by which of the 4060's outputs are logically combined by AND gate U1b. At present we are using outputs q9, q10, q13 of the 4060 but you could use a 3-pole multi-way switch to select those or other outputs. (N.b the 4060 doesn't have a q11 output).

I am fairly SURE that I will need to change the component numbers on the clock circuit because it will/would be confusing

You're right. If you can post a pic of the circuit with the new numbering then we'll be singing from the same hymn sheet to avoid further confusion .

 

will do that today after church. so 20 minutes, 40 minutes and 60 minutes is feasible?

 

here is what I came up with

 

Ok. And here's how you could modify the 'clock' by using a 3P3T switch to select times of ~ 24 min, 30 min and 57 min.

 

OUCH!!!! that makes my head spin.....but...every problem has a solution, right? OK... the way I constructed the timer circuit, or I should say, the way I used the pins from the 4060 TO the 4073B is as follows. this is from the original design. for U1a I used pins 11, 12 and 13. U1b I used pins 3, 4 and 5. U1c I used pins 1, 2 and 8. my understanding is I can use each group (of3) because they ALL operate the same? AND that I could choose which ever combination I want to facilitate simplest the wiring path. (because for now I am using a single sided copper clad board.

my point being "before" I make a mistake, electronics are NOT FORGIVING. I can use any group, BUT, if your initial pin selection was different from mine our results "may not" be the same????? so I am thinking, "what if Alec chose 1,2, and 8 for U1a??? instead of my choice of 11, 12 and 13.

is that a legitimate question???

 

I didn't show any specific pin numbers for the 4073B connections. The mod can use the same (correct) pins you are now using, as described above.
Just to confirm: the 4073B contains 3 equivalent AND gates, each gate having a set of 3 equivalent inputs.

 

i remember my dad telling me to "keep it simple" don't over think it, and a bunch of other stuff I wish he was still here to talk about. 30 minutes. just 30, nothing else. it's close enough to 20 and close enough to 45. and it will take half the time to test to see if it works. how do I do that? I understand it better when I build it. actually.... I understand it better when I build it, they FRY it, and then figure out WHY! it's not frustrating anymore, it's just fun and fascinating! I wish I would have started when I was 5.

 

The Q outputs of the 4060 go high ~N minutes after the 4060 gets reset, according to the following:-
Q........N
Q9.....3
Q10...6
Q12...24
Q13...48

30 mins = 24 mins + 6 mins, so you use Q12 and Q10 as two of the AND gate (U1b) inputs and use Vdd as the third input.
This is what happens when S2 is in the centre position.

 

no, I don't want to add a switch, just change the existing circuit in post 226 to 30 minutes (+-) I want to change the one I already made and after that work on a multi selection.

 

I understand the concept (binary) 1+1 = on or off, 1 + 0 = and so on. when I build one circuit, I kinda "get it". then when a change is made I have a comparison. a schematic is like a road map to me. I can actually SEE the paths. then I can experiment. I could have 9 minutes or 27. I just haven't learned enough to....well I got a long way to go, I know. data sheets are great for those who know what they mean. I build stuff and then figure out what it is actually doing. the more they get moved around and I see how the interact, the more stuff I think of building. or I should say, the more stuff I think I can build with the stuff I know! I and haven't EVEN scratched the surface.

 

I don't want to add a switch, just change the existing circuit in post 226 to 30 minutes (+-) I want to change the one I already made and after that work on a multi selection.

Fine. Omit switch S2.
30 mins = 24 mins + 6 mins, so instead of Q9,Q10,Q13 you use Q12 and Q10 as two of the AND gate (U1b) inputs and use Vdd as the third input.

 

ok, U1b, I use pins 3,4,5 with 6 as output.
q9 to 3
q10 to 4
q13 to 5

so now.....U1b
q10 to 3
q12 to 4
pin 16 of cd4060 to pin 5 (Vdd)

???????

 

Yup. Or you could connect pins 5 and 14 of the 4073 together to get Vdd as the third gate input.

 

q14 of the CD4060

to pin 5 of U1b of the CD4073

U1a and U1c remain the same

?

 

q14 of the CD4060 to pin 5 of U1b of the CD4073

No. You don't use q14 (unless you want a delay of ~96 minutes or more).

U1a and U1c remain the same

Yes.

 

OK, I got that, the 14 pin is on the 4073. so next question, if I want 24 minutes how will I determine the third input. would I simply bridge/connect pins 3 and 4 of U1b then connect them both to q12? AND use pin 14 of the 4073 to pin 5 of U1b?

 

That would do it. Or pins 3,4,5 could all be connected to q12.