Damm. Have a switch that comes with 12v when activated. Ok then i will use an relay to act as S1.

OK, now I see what you were thinking. Yes, a relay for S1 will work. It can be a tiny reed relay, since there's almost no current.

 

To be clear to the TS, the circuits in #1 and #3 are *not* equivalent. The circuit in #1 will not work as intended; the output will not toggle with each successive button press. Neither will the circuit in #11.

For this type of circuit (#3 and #10) to work, note that neither end of the switch is connected to either Vdd or GND. That is critical to the circuit's operation. In both #1 and #11, one end of S1 is connected to the +12. This will not work. For the circuit in #11 to work correctly, delete the connection between the R1-C1-S1 node and the +12 V.

ak

 

edited scehmaticd . when s1 is activated (pulse 12v) it shoild toogle the relay K1

 

Hello

This is kinda what AK is suggesting.
I've changed the BJT to a Mosfet to relieve the output current requirement of the CD40106B.
You can replace the CD40106B with CD4093B connected as inverters if you like..

 

40106 or 4093 is not any problem. But the 2n7002. What one to use ?
https://dk.farnell.com/on-semiconductor/2n7002/mosfet-n-60v-sot-23/dp/9845313RL?st=2n7002

 

40106 or 4093 is not any problem. But the 2n7002. What one to use ?
https://dk.farnell.com/on-semiconductor/2n7002/mosfet-n-60v-sot-23/dp/9845313RL?st=2n7002

I don't think you need to use that exact MOSFET. As long as it's N channel and can supply enough current to the output relay.

 

Some of those i can find says 5v or 10v.. do it matter ?

 

40106 or 4093 is not any problem. But the 2n7002. What one to use ?
https://dk.farnell.com/on-semiconductor/2n7002/mosfet-n-60v-sot-23/dp/9845313RL?st=2n7002

If you want a through hole MOSFET, use 2N7000.

 

Some of those i can find says 5v or 10v.. do it matter ?

Use the 2N7000 TO-92 version (Not 2N7002 although it wouldn't hurt). The 2N7000 is good for 200mA and the TO-92 is not SMD so you can easily solder it to a board.

eT

 

Some of those i can find says 5v or 10v.. do it matter ?

Your circuit uses 12V, which is high enough to turn on any MOSFET. So I think it does not matter.

 

HAve found that i have all the componentes except one,
Can i substitude the Reed Relay (K2) with an Optocoupler 4N33. ?

And how ?

 

and then there is this...

 

and then there is this...

That circuit, as discuessed in another thread on here has a problem with a load which has capacitance. When the button is pressed to turn off, the capacitance maintains the output voltage then when the button is released the output voltage, via the 100k resistor, keeps the left hand transistor and therefore the MOSFET swoitched on.

 

That circuit, as discuessed in another thread on here has a problem with a load which has capacitance. When the button is pressed to turn off, the capacitance maintains the output voltage then when the button is released the output voltage, via the 100k resistor, keeps the left hand transistor and therefore the MOSFET swoitched on.

... Solved with a Schottky diode and resistor?

 

It

... Solved with a Schottky diode and resistor?

It was solved with a different circuit arrangement which eliminated the problem at source and didn't need the voltage drop of a diode. However I can't find that thread.

 

Just as a side note if you have not already done so, the CD4011 is a quad NAND chip and you are using two of the four gates. All unused inputs should be tied to VCC or GND so the inputs of the remaining two gates need to go to either VCC or Ground the outputs matter not and can be left floating.

Ron

 

reed relay. Use instead of button BP..
not output

 

reed relay. Use instead of button BP..
not output

If you mean "can I substitute a reed relay contact for the pushbutton contact?". Yes. As long as you dedicate a contact to replace the button contact.

eT

 

It is difficult to read circuit intent from your drawing style.

This is what I transcribed (substituting inverters for NANDs) and put in a more conventional layout:
View attachment 191421
The circuit has some issues.

1. You're loading the output of a logic gate that you need to maintain proper logic levels.
2. You don't have a snubber diode on the coil.
3. C2 might need to be larger. I have used this circuit and typically use 100nF.

What is the coil resistance?
Use the unused NAND gates to buffer the output of the flip flop.

The circuit is not the same as the original post. In that post one side of the switch went to +12 volts. That circuit would switch on when the button was pressed, but I did not see a way for it to switch off. It will start in an indeterminate state and will probably not change when the button is pushed.
Copy a normal bistable circuit and it may work, or use a CD4013 dual FF with a capacitor to assure a predictable state at power on, and your alternate action will be assured. But only if there is no contact bounce. It is also possible to have the circuit switch when the button is released, musch less likely to be falsely triggered.

 

That circuit, as discuessed in another thread on here has a problem with a load which has capacitance. When the button is pressed to turn off, the capacitance maintains the output voltage then when the button is released the output voltage, via the 100k resistor, keeps the left hand transistor and therefore the MOSFET swoitched on.

The thread I was looking for is below. See #12.
https://forum.allaboutcircuits.com/...oads-but-not-with-others.163057/#post-1431294