Hi,Using the transfer function, simulate the system using operational amplifiers. Please help, I don't have any idea where to start.
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Hi ZapperDid they not discuss this in your class?
Thanks a lotHi,
The simplest way to handle this is to turn this into an equation where the form is in the form of all integrators. You'll find 3 integrators will be used. You can then implement using op amps set up as integrators. You can then simplify that if you like but may not be necessary because that will in fact form the system just like that.
Does that help, or do you want more help?
Yes I know how to find Poles and Zeroes, the only thing I don't know are the actually steps I need to follow in order to solve the problem.
- Do you know what poles and zeros are?
- Do you know how to find them?
Step 1: It is an easy task to find the poles of the function (zeros of the denominator). All three poles are simple integer numbers (one pole must be guessed - start with the most simple assumption: A negative real pole). Knowing one pole, you can find the remaining two poles.Yes I know how to find Poles and Zeroes, the only thing I don't know are the actually steps I need to follow in order to solve the problem.
You're welcome.Thanks a lot
Am I wrong - or is the function to be realized (post#1) of third order?Starting with:
y/x=(s+a)/(s^2+b*s+c)
Hi there,Am I wrong - or is the function to be realized (post#1) of third order?
However, when ther 3rd-order function is split into a series connection of a 1st as well as 2nd-order expression, the proposed approach seems to be a good method for realizing the 2nd-order part.
Yes, this is really a good and very effective method to derive a block diagram from a given transfer function - based on (positive) integrator units.This approach can be found in a U.S. Navy handbook. It's also quite intuitive.
The differential form views the integrators as differentiators by viewing the signal flow in reverse.
Yeah, that's the only drawback, we need noninverting integrator units. That's a shame because it's so much easier to form an op amp summing junction on the inverting terminal. That may leave us with the requirement that we also need two regular op amp inverting amplifiers.Yes, this is really a good and very effective method to derive a block diagram from a given transfer function - based on (positive) integrator units.
I just have tried to replace both positive integrators with negative units (-1/s), which are basic units (Miller integrator) in circuit theory.Yeah, that's the only drawback, we need noninverting integrator units. That's a shame because it's so much easier to form an op amp summing junction on the inverting terminal. That may leave us with the requirement that we also need two regular op amp inverting amplifiers.
Hi,I just have tried to replace both positive integrators with negative units (-1/s), which are basic units (Miller integrator) in circuit theory.
The consequences are:
* The x-signal must be multiplied with "-1" (instead of "+1) before it is fed into the 2nd integrator;
* The feedback factor "b" for the 2nd integrator must now be positive (instead of "-b")
In principle, there are three topologies for a non-inverting integrator:I think there is a way to do it with positive integrators using op amps but i'd have to remember how it is done.
Hi,In principle, there are three topologies for a non-inverting integrator:
* Use of a second opamp (inverting) - either in series with the inverting Miller integrator or within its feedback loop.
* NIC-integrator (Negative Impedance Converter): Risky design, close to instability
* BTC integrator (Balanced Time Constants): R-C lowpass at the non-inv. input together with R-C negative feedback (like Miller integrator).
Hello again,In principle, there are three topologies for a non-inverting integrator:
* Use of a second opamp (inverting) - either in series with the inverting Miller integrator or within its feedback loop.
* NIC-integrator (Negative Impedance Converter): Risky design, close to instability
* BTC integrator (Balanced Time Constants): R-C lowpass at the non-inv. input together with R-C negative feedback (like Miller integrator).
by Aaron Carman
by Duane Benson
by Duane Benson