I just built this circuit that has a CA3080 op amp at the output, i understand this device isn't a regular op amp but i always thought chips needed a positive and a 0V or negative on the other supply pin, i havn't measured whats on pin 4 in this circuit but clearly it doesn't go to 0V or negative, the data sheet states a 0V supply.

Just curious since the circuit is working fine.

 

i havn't measured whats on pin 4 in this circuit but clearly it doesn't go to 0V or negative, the data sheet states a 0V supply.

There's nothing that says the positive and negative supplies for an opamp need to be the highest and lowest voltages in the circuit.

There's a voltage divider on the V- pin. It's at 1.62V.

 

There's nothing that says the positive and negative supplies for an opamp need to be the highest and lowest voltages in the circuit.

There's a voltage divider on the V- pin. It's at 1.62V.

But the two questions that come to my mind are:

What is the purpose of having the negative supply elevated?

What is the purpose of powering the opamp with a supply having well over 1 kΩ of resistance?

Assuming it's not a mistake, I have to assume that it's some kludged-up distortion effect.

 

Assuming it's not a mistake, I have to assume that it's some kludged-up distortion effect.

There's so much wrong with that schematic (for instance, using a box instead of an opamp symbol for the CA3080), that I'm not inclined to try to analyze it.

There's a weak virtual ground formed by R14 and R15, so the V- voltage would allow the output to just about get down to the virtual ground voltage.

 

There's so much wrong with that schematic (for instance, using a box instead of an opamp symbol for the CA3080), that I'm not inclined to try to analyze it.

I'm not going to get bent over someone using the symbol that the simulator provides instead of taking the time to make their own, which likely involves learning how to create symbols and tie them to the device model.

 

There's so much wrong with that schematic (for instance, using a box instead of an opamp symbol for the CA3080), that I'm not inclined to try to analyze it.

There's a weak virtual ground formed by R14 and R15, so the V- voltage would allow the output to just about get down to the virtual ground voltage.

All i can tell you is that despite any wrongs in the schematic, the circuit works very well and does exactly what i wanted

thanks for the replies everyone.

 

All i can tell you is that despite any wrongs in the schematic, the circuit works very well and does exactly what i wanted

thanks for the replies everyone.

Try connecting the negative supply of the opamp to the negative power supply rail and see if it actually makes a significant difference.

 

Try connecting the negative supply of the opamp to the negative power supply rail and see if it actually makes a significant difference.

My circuit isn't on breadboard, it's laid out on veroboard and since it's working well i'm not going to mess with it... time to fit it in a box me thinks