- Joined Apr 7, 2008
+1The only way you could ever achieve an "ideal pulse" would be if there was no such thing as capacitance or inductance.
And no such thing as transit time.The only way you could ever achieve an "ideal pulse" would be if there was no such thing as capacitance or inductance.
Well maybe, sorta. Current electricity (moving charge) has very little energy in most electrical transmission circuits and the electrical energy that provided the KE (moving charge) to electrical charge is generally transformed to 'heat'. The pulse we see in a normal digital signal is a representative (with possible reflection patterns) of the EM field(s) that actually transports electrical energy using free charge as the pathway/wave-guide. The fields and charges work as a system in current electricity.Electric currents, like current electricity, means the moving of electrical energy from one place to another via the moving of electrons. We can manipulate electrons to give a particular result. A digital pulse is a waveform like any way form it must be defined to make sense. The digital pulse you provided is a visual representation and the product of manipulating electrons define by its rise time, fall time, bandwidth, amplitude xcetera, and it's proven mathematically. I speak in generalities. And now I am at a high potential for "Cannon fodder".
The ninth thread I'm hoping was appropriate for the question?My apologies if I may have caused confusion. I do very much enjoy reading the answers you provide nsaspook! And I am blown away that you even quoted me, and by the way I'll takehi friends
why in digital pulse there rise time, fall time .. etc and the delay time
From someone of such high caliber.Well maybe, sorta
Inductance and capacitance and resistance are inherent in most circuits.
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