That depends upon many factors -- I will say this this --- Ignorance is the principal factor in poverty!

Education 'opens doors' as it were -- to what advantage you put said opportunity remains up to you

 

Previous study and research has made my life and millions of others, longer, healthier and much more comfortable.

The reason I study is so I don't have anyone else to do my thinking for me.

Study always helps other study.

And with a good knowledge base, when a new problem comes up, your chances of independent solution increases.

Exactly! Thank you!!!

 

Ignorance is the principal factor in poverty!

I am satisfied with you because you will not believe when i was in 6th class school i started bring cheating paper slip in examination hall for passing hindi an other subject due to which i am literate but mind is illiterate

 

Previous study and research has made my life and millions of others, longer, healthier and much more comfortable.

The reason I study is so I don't have anyone else to do my thinking for me.

Study always helps other study.

And with a good knowledge base, when a new problem comes up, your chances of independent solution increases.

please tell more to explain how?
your word can help other.

 

I am satisfied with you because you will not believe when i was in 6th class school i started bring cheating paper slip in examination hall for passing hindi an other subject due to which i am literate but mind is illiterate

The best only way to overcome past mistakes is with hard work and good decisions in the present! You seem to be off to a good start in that regard!!!

 

The bestonly way to overcome past mistakes is with hard work and good decisions in the present! You seem to be off to a good start in that regard!!!

At that time i was not able to judge myself that little mistake will increase and destroy my life

 

At that time i was not able to judge myself that little mistake will increase and destroy my life

The good news is that your life needn't be destroyed! -- Earnest action now will get you back 'on course' -- I promise!!!

 

Hello,
How to solve this i am working in Aptitude ?
The present worth of Rs. 2310 due 2

years hence, the rate of interest being 15% per annum, is:

A.
Rs. 1750
B.
Rs. 1680
C.
Rs. 1840
D.
Rs. 1443.75

You will not believe that how this thread start i was walking to home some student smaller than me was talking about this aptitude so i decided to start aptitude.

 

Anyway, let move to another question which will increase intelligence an money.

 

Let's focus on Wbhan's exercise...OK?

 

Here it is:

The equivalent resistance, Req, of two resistors R1 and R2, placed in parallel is given by

R_{eq} \: = \: \frac{R_1 \cdot R_2}{R_1 \: + \: R_2}
" style="-x-ignore: 1">

Show that, if R1 ≤ R2, then

Req ≤ R1

and that

(R1)/2 ≤ Req ≤ (R2)/2

NOTE: I added a lower limit to the last one.

This is a very useful result as it allows you to place bounds on the equivalent resistance of parallel resistors (or instructor, or series capacitors) by inspection. And we've seen how useful bounds can be.

 

Anyway, let move to another question which will increase intelligence an money.

Don't worry about money now -- Trust me! Mathematical and scientific talent is and always will be at a premium!

 

@RRITESH KAKKAR

It's easier to read with the formatting intact -- so here it is:

Here it is:

The equivalent resistance, Req, of two resistors R1 and R2, placed in parallel is given by

\(
R_{eq} \: = \: \frac{R_1 \cdot R_2}{R_1 \: + \: R_2}
\)

Show that, if R1 ≤ R2, then

Req ≤ R1

and that

(R1)/2 ≤ Req ≤ (R2)/2

NOTE: I added a lower limit to the last one.

This is a very useful result as it allows you to place bounds on the equivalent resistance of parallel resistors (or inductors, or series capacitors) by inspection. And we've seen how useful bounds can be.

 

Don't worry about money now

Right now you are in USA, are you belong to US?

 

Yes I am a US national -- Let's focus on the problem -- Do you see the implicit upper limit?

 

...and inasmuch as we're discussing resistors (which cannot have values < 0) there's an implicit lower limit also...

 

This is a very useful result as it allows you to place bounds on the equivalent resistance of parallel resistors (or inductors, or series capacitors) by inspection. And we've seen how useful bounds can be.

What to solve in this?
i have seen it is true.
Show that, if R1 ≤ R2, then
Req ≤ R1
and that
(R1)/2 ≤ Req ≤ (R2)/2
let R1 be 5ohm and R2 be 7ohm
Req= 2.91ohm

 

The object of the exercise is to prove the following:

Show that, if R1 ≤ R2, then

Req ≤ R1

and that

(R1)/2 ≤ Req ≤ (R2)/2

 

Hint: Start by stating the upper and lower limits of (R1*R2)/(R1+R2) --- Bearing in mind that resistors cannot have negative values...

 

The object of the exercise is to prove the following:
Show that, if R1 ≤ R2, then
Req ≤ R1
and that
(R1)/2 ≤ Req ≤ (R2)/2
Start by stating the upper and lower limits of (R1*R2)/(R1+R2)
lower limit may be 0 (short) and infinity (open)