Via the the stipulation that R1 ≤ R2 and the implicit lower limit of R1 = 0 (owing to the fact that it is a resistor)

So:
Req=(0*R2)/(0+R2) Indeed yields a lower limit of 0 for Req

So... what's the upper limit or Req?

 

upper limit may be infinity (open)

 

upper limit may be infinity (open)

Resistances are taken to be finite --- Don't let that confuse you, just state the upper limit algebraically (i.e. don't attempt to solve for a numeric value)

 

Resistors are taken to be non-infinite --- Don't let that confuse you, just state the upper limit algebraically (i.e. don't attempt to solve for a numeric value)

It may be megaohm

 

I repeat, please state the upper limit of the expression algebraically

 

I repeat, please state the upper limit of the expression algebraically

10MΩ

 

That is merely an arbitrary guess and it is not a symbolic expression!

---Consider this ---

We've already decided the lower limit = 0

Given that:
Req=(R1*R2)/(R1+R2)

And that
R1 ≤ R2

And that:
R1 ≥ 0 (owing to the definition of [dissipative] resistors) (Granted a 0Ω 'resistor' is not dissipative -- but 'what the hey')

we may state the lower limit of Req algebraically thus:

Req(Minimum)=(0*R2)/(0+R2) ------- Get it?

Now express the upper limit in similar manner

 

Req(Minimum)=(0*R2)/(0+R2) ------- Get it?

the Req=infinity

 

@RRITESH KAKKAR

Inasmuch as this this exercise was submitted by @WBahn -- I feel he should be present to guide its solution (IOW -- I don't want to give too many 'unauthorized hints') --- So, would you like me to post another problem for now???

 

sure.

 

sure.

Ok give me a few minutes...

 

A board 50 inches long is to be divided into four parts. Each part is to be 1 inch longer than the next part. What will be the lengths of the four pieces?

 

Come on! I gave you this easy exercise as a 'soft start' (impatiently tapping fingers....)

 

Each part is to be 1 inch longer than the next part

next or previous part?

 

All you need do is find the length of the shortest (or longest) piece -- thence calculate the lengths of the other three...

 

A board 50 inches long is to be divided into four parts. Each part is to be 1 inch longer than the next part. What will be the lengths of the four pieces?

let the length of smaller be x.
so total length of 3 part will be 50-x
------------------------------50inch
x | | | (50-x)

 

What's with the vertical lines?

 

Hint: this is a very simple problem -- perhaps you're overcomplicating it?

 

What's with the vertical lines?

drawing the line 50inch

 

A board 50 inches long is to be divided into four parts. Each part is to be 1 inch longer than the next part. What will be the lengths of the four pieces?

ok, 44 3 2 1

no