Hello,
Yesterday, i was at home.
as R is 1 ohm.
so, P & Q as you said Hint 1: Note that the resistance of the semi-infinite 'section' is not altered via removal of preceding 'stages'
it should 3 ohm
1+1+1=3

That is indeed the resistance of a single 'stage' just as two 'stages' have a resistance = 2.75Ω and three stages a resistance = 2.6Ω, etc... But the point is that the semi-infinite network remains infinite in extent (towards the 'right') hence its resistance is not changed via 'removal' of any number of 'stages' from the left -- as I said, that first hint is 'huge'

PS --- Thanks for returning!

 

PS --- Thanks for returning!

what is PS

 

That is indeed the resistance of a single 'stage' just as two 'stages' have a resistance = 2.75Ω and three stages = 2.6Ω, etc... But the point is that the semi-infinite network is remains infinite (towards the 'right') hence its resistance is not changed via 'removal' of any number of 'stages' from the left as I said that first hint is 'huge'

Sorry i don't get it.

 

then,
1+1.3+1=3.3

So putting a 3 Ω resistor in parallel with a 1 Ω resistor would yield a 1.3 Ω resistor?

Please show your calculations.

Any time two resistors are placed in parallel, the combined resistance must be less than the smaller of the two (it must also be less than half of larger of the two).

That, in and of itself, is a good problem for you. So to state it formally:

The equivalent resistance, Req, of two resistors R1 and R2, placed in parallel is given by

\(
R_{eq} \: = \: \frac{R_1 \cdot R_2}{R_1 \: + \: R_2}
\)

Show that, if R1 ≤ R2, then

Req ≤ R1

and that

Req ≤ R2/2

 

what is PS

PS = Post Script ~ "additionally" or "Oh, by the way" Used when one wishes to append a note to a missive...

 

what is PS

It's stands for "post script", a reference to a note added to a letter after it has been signed (think back to the days before word processors when letters were hand-written or, at best, hand typed). The "post" means "after" and the "script" refers to the handwritten signature. Or, an equivalent view, is that it literally means "script (i.e., writing) that comes after." If you closed a letter and signed it and then wanted to add something to it, you wrote "PS" before additional material. If that happened again, you wrote "PPS" for "post post-script".

 

 

Sorry i don't get it.

Well... the infinite network has a finite resistance (the value which you wish to determine) -- You know the resistance of, for instance, a single stage -- your next move would seem obvious?

 

So putting a 3 Ω resistor in parallel with a 1 Ω resistor
R1=3 ohm
R2=1 ohm
Req=R1xR2/R1+R2
Req= 3/4=.75ohm

 

So putting a 3 Ω resistor in parallel with a 1 Ω resistor
R1=3 ohm
R2=1 ohm
Req=R1xR2/R1+R2
Req= 3/4=.75ohm

I see you are working at this and that's good! That said please consider the fact that merely obeying traffic regulations doesn't guarantee you'll get to where you wish to go

 

What is the answer

 

What is application of resistance in star-delta connection

 

What is the answer

Please take your time to work on it and think about it --- There's no time limit, nobody is rushing you!

 

Sorry i don't get it.

I figured this would be a point of confusion. Perhaps this will help:



Take the original circuit and name nodes P' and Q' and then break the circuit into two portions at the black hash marks. This gives you the two circuits directly below it.

The key is to recognize that the resistance between P' and Q' must be the same as between P and Q. Do you see that this must be the case and why?

 

So putting a 3 Ω resistor in parallel with a 1 Ω resistor
R1=3 ohm
R2=1 ohm
Req=R1xR2/R1+R2
Req= 3/4=.75ohm

Yes. So that is the equivalent resistance of the middle 1 Ω and the everything to the right of it (assuming your answer of 3 Ω total was correct). So what would that give you for the total resistance of the whole thing?

 

What is the answer

Come on! You have been making such good progress. Don't give up now!

 

Do you see Wbhan's point? The network to the right remains the same despite presence or absence of 'preceding stages'

 

So putting a 3 Ω resistor in parallel with a 1 Ω resistor
R1=3 ohm
R2=1 ohm
Req=R1xR2/R1+R2
Req= 3/4=.75ohm

That is indeed the resistance of a single 'stage' just as two 'stages' have a resistance = 2.75Ω and three stages a resistance = 2.6Ω, etc.
PQ = 1+.75+1=2.75

 

I'm only sticking around to see how long this ridiculous thread gets before it dies. My guess: 500 posts, MINIMUM.

But have you noticed that HP has gotten him engaged and he is actually putting forth effort and coming up with solutions?

 

That is indeed the resistance of a single 'stage' just as two 'stages' have a resistance = 2.75Ω and three stages a resistance = 2.6Ω, etc.
PQ = 1+.75+1=2.75

Yes!

But now you need to ask the "does it make sense" question.

IF the resistance between PQ is 3 Ω, then if follows that the resistance between PQ is 2.75 Ω.

What does this conclusion tell you about the claim that the resistance between PQ is 3 Ω?