I see, Q2 goes to pin 8, danyk never mentioned that.. he only said "This is done by shorting the emitter and collector of one of optocouplers" not any transistor.. thanks.Short out Q2 c/e terminals, this will keep the chip power on and prevent shutdown.
As for the opto led, yes this is the one that regulates the voltage.
Oh, thank you! but I've tried shorting out every octocouplers emitter/collector one by one. and it does not matter which one i short ut, the supply won't power on at all..IC2 is feedback.
IC3 is the ON/OFF
Hmm i didn't think of that, Definetly going to try it, I'm used with linear power supplies, pretty new with this whole switching thing hehe, Will report back in an hour or so!How about modify the OVP to handle your voltage ?
Since you have gone this far, it would be nice.
Thanks then I'll know what to start looking for.The Ovp will be using a Tl431 to fire an opto, or it may use another chip to do the same job....
I don't mean in series with the output.You cant limit the current by putting a shunt resistor in series with the output, an atx psu monitors the current in the pulse transformer, and then uses that to switch off the oscillator on the I-sense pin.
As for the capacitors, all the Atx psus i have made variable will only go upto 33V at maximum, so i use 63v capacitors for safety.
Yes and that is the one i meant to change. But in my case it was 0.15 instead of 0.22.Current limit on your diagram is provided by R7, increasing it lowers the current output and vice-versa...
http://danyk.cz/s_atx06h.png
Awesome thank you! Sounds weird tho, i thought that the resistance had to increase for the current to lower..According to the datasheet, Isense pin needs 1V to shutdown, so your resistor needs to be 67mOhms (0.067)
by Jake Hertz
by Jake Hertz
by Duane Benson
by Jake Hertz