three identical 12V batteries are connected in parallel across a load which consists of 1.2K Ohm, 2.2K Ohm, and 3.3K Ohm resistors in parallel. that is the value of the current supplied by each?

I figured that since the batteries are in parallel then my Vtotal is 12V. I used teh reciprocals of the resitors to get Rtotal of 629 Ohm. I got Itotal of 19 milliAmp. I then divided 12V by each resistor. So R1 is 10mA, R2 is 5mA, R3 is 3mA. Which adds up to 18mA.

 

"The current supplied by each" -- each battery?

Solve the equivalent resistance for the three resistors.
Solve the voltage for the three batteries.
Apply Ohm's Law.

--Rich