Help Understanding Conventional Vs Electron Current As Relates To Polarized Components

MrAl

Joined Jun 17, 2014
13,720
Check your diode datasheet and curves for more understanding of the humble diode.
Hi,

I think it was Bob Pease originally with National Semiconductor that did articles on the illustrious diode. He even went into detail about temperature characteristics and plotted the responses. The articles are probably still on the web somewhere. They are more or less for advanced study.
 

MrAl

Joined Jun 17, 2014
13,720
Analogies are fine but as usual things are more complex than they seem at first glance.

With a CRT that electron KE from motion is useful but remember that pure KE is no longer electrical energy. Some electrical energy was transformed during the acceleration from an electric field into the energy of moving mass with a charge. it's very small charged rock aimed at other small charged rocks.


https://sciencedemonstrations.fas.harvard.edu/presentations/crt-paddle-wheel
https://fathomingphysics.nsw.edu.au..._VCalisa_Phys_Teach_vol_52_iss_3_142_2014.pdf
Hi,

That electron still retains a magnetic field and responds to other magnetic fields, thus it must retain an electric field also and that is evident from observing how a CRT oscilloscope works and how a CRT television works. The o'scope uses an electric field to steer that lonely little electron while the TV uses a magnetic field.
 

nsaspook

Joined Aug 27, 2009
16,340
Hi,

That electron still retains a magnetic field and responds to other magnetic fields, thus it must retain an electric field also and that is evident from observing how a CRT oscilloscope works and how a CRT television works. The o'scope uses an electric field to steer that lonely little electron while the TV uses a magnetic field.
Sure it does, that's why it's a small charged rock. The electron KE from the CRT electric field acceleration excites (the conversion of KE back to EM energy) the phosphor it hits (Coulomb’s repulsion) while the charge (the electron) is collected and is circulated like in a normal circuit.

https://en.wikipedia.org/wiki/Cathodoluminescence

https://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.1062.7970&rep=rep1&type=pdf
In a CRT, one electron from the cathode is taken out from the heated Ba on BaO layers on metal cathode into
vacuum [1]. The electron taken from the cathode is accelerated by the anode potential (25 keV). The accelerated electron penetrates a phosphor particle to generate CL light.
The incident electron that has penetrated in to the phosphor particle collides (Coulomb’s repulsion) with lattice sites (atoms or ions) in the phosphor particle. Each collision with
the lattice atoms (and ions) generates one secondary electron in the space between lattice atoms, leaving a hole in the orbital shell of the atoms. The incident electron in the
phosphor particle collides with lattice sites more than 3,000 times before the energy of the incident electron attenuates to the phonons that disappear in the phosphor particle by
heat. Consequently, 3,000 pairs of free electrons and holes in the phosphor particle are generated by one incident electron in the phosphor particle. The creation energy of a pair
of electron and hole is 3 Eg, where Eg is the band gap of the phosphor crystal (particle) [2]. The generated pairs of
free electrons and holes in the phosphor particle are called “electron-hole pairs.” In the phosphor particle, one electron-hole pair recombines at only luminescent center and
disappear from the phosphor particle. The recombination of the electron-hole pair at the luminescent center releases a
photon in the visible light without heat. Consequently, the quantum efficiency, which is the number of photons to the number of incident electrons, becomes ηq > 3,000 [3].
 
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MrAl

Joined Jun 17, 2014
13,720
Sure it does, that's why it's a small charged rock. The electron KE from the CRT electric field acceleration excites (the conversion of KE back to EM energy) the phosphor it hits (Coulomb’s repulsion) while the charge (the electron) is collected and is circulated like in a normal circuit.

https://en.wikipedia.org/wiki/Cathodoluminescence

https://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.1062.7970&rep=rep1&type=pdf
I think it is interesting because it is like a flow of current. The magnetic field is like that we see from a wire with current flow.
I did a YouTube video on this to illustrate the Lorentz force. All other videos like to use a wire and so they have to have a huge current and big magnet. With an CRT oscilloscope you can show it happen with a refrigerator magnet.
I suppose we could calculate the velocity of the particle(s) too.
 

nsaspook

Joined Aug 27, 2009
16,340
Well, it is a current (with all the properties you would expect from a current) that could be electrons, protons or ions being accelerated with KE measured usually in electron volts combined with current (Conventional for + or - charges) as a measure of beam luminosity

https://en.wikipedia.org/wiki/Electronvolt
In physics, an electronvolt (symbol eV, also written electron-volt and electron volt) is the measure of an amount of kinetic energy gained by a single electron accelerating from rest through an electric potential difference of one volt in vacuum. When used as a unit of energy, the numerical value of 1 eV in joules (symbol J) is equivalent to the numerical value of the charge of an electron in coulombs (symbol C). Under the 2019 redefinition of the SI base units, this sets 1 eV equal to the exact value 1.602176634×10−19 J.[1]
https://www.lhc-closer.es/taking_a_closer_look_at_lhc/0.beam_current
Different devices are used for this goal, but the LHC circulating beam current measurement is provided by current transformers. They are based in the Measurement of the beam’s magnetic field. This kind of devices are non-destructive, they have no dependence on beam energy and they have lower detection
https://cds.cern.ch/record/941318/files/p361.pdf
 

MrAl

Joined Jun 17, 2014
13,720
Well, it is a current (with all the properties you would expect from a current) that could be electrons, protons or ions being accelerated with KE measured usually in electron volts combined with current (Conventional for + or - charges) as a measure of beam luminosity

https://en.wikipedia.org/wiki/Electronvolt


https://www.lhc-closer.es/taking_a_closer_look_at_lhc/0.beam_current


https://cds.cern.ch/record/941318/files/p361.pdf
It's also interesting that we now have another phenomenon involving mass movements of electrons.
In a wire, they interact with a number of things that impedes their flow and that's a large part of the operation.
In a CRT, they shoot across a vacuum.
In each case they are interacting with something else and that's a large part of the operation mode.
Now also they can interact with each other, at very low temperatures approaching absolute zero, where they can swirl in a vortex which sort of looks like turbulent flow which means they collectively act like a fluid due to quantum effects with each other, and that's the main part of operation there.
I supposed we can also say that in some super conductors they act like they are exhibiting laminar flow, which again is like a fluid.
In these cases the electrons are interacting with each other.
 

BobaMosfet

Joined Jul 1, 2009
2,211
First, please accept my apology for not posting a schematic. I did think about it, but I do not know how to use schematics yet, nor the tools to create them. I am still working my way through the first volume of the text book on this website.

I really appreciate this answer. It was extremely helpful in wrapping my mind around this. Thank you so much!
This may help you-

Title: Understanding Basic Electronics, 1st Ed.
Publisher: The American Radio Relay League
ISBN: 0-87259-398-3

Regarding polarity- which is voltage-related and current flow, current flow makes perfect sense when you remember polarity determines the direction that current flows.

Electrons are negatively charged. If you have two points (or 2 poles), and one pole has fewer electrons, and the other pole has more electrons, then by definition, the pole with the least electrons is considered 'positive' in relation to the other pole, which is more negative.
 
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