Hello!
I'm working on a project that involves a PCB with an IR diode (emitter) and photodiode (receiver) that will be installed on one side of a chamber. On the other side of the chamber there will be a reflector. The light emitted by the IR diode will cross the chamber, and reflect back onto the emitter.
The purpose of this is to be able to measure particles of different sizes in the chamber by obscuring the light.
For the IR diode I will be using the SFH 4258S for it's high power and narrow beam.
The driver circuit I have designed is a constant current source that can drive it with 0 - 100mA.
What I cannot seem to extract from the datasheet is the relationship between the forward current and the optical power output.
I assume the "Relative radiant intensity" graph shows it, but I cannot seem to fully understand this graph or the (Ie / Ie) units.
For the photodiode I will be using the BPW 34S.
I will be using a TIA circuit for converting the generated current into voltage, and measuring with an ADC.
For this component I cannot seem to understand the relationship between the incident optical power and the current generated by the photodiode.
Any information that can point me in the right direction will be very much appreciated, thanks in advanced!
I'm working on a project that involves a PCB with an IR diode (emitter) and photodiode (receiver) that will be installed on one side of a chamber. On the other side of the chamber there will be a reflector. The light emitted by the IR diode will cross the chamber, and reflect back onto the emitter.
The purpose of this is to be able to measure particles of different sizes in the chamber by obscuring the light.
For the IR diode I will be using the SFH 4258S for it's high power and narrow beam.
The driver circuit I have designed is a constant current source that can drive it with 0 - 100mA.
What I cannot seem to extract from the datasheet is the relationship between the forward current and the optical power output.
I assume the "Relative radiant intensity" graph shows it, but I cannot seem to fully understand this graph or the (Ie / Ie) units.
For the photodiode I will be using the BPW 34S.
I will be using a TIA circuit for converting the generated current into voltage, and measuring with an ADC.
For this component I cannot seem to understand the relationship between the incident optical power and the current generated by the photodiode.
Any information that can point me in the right direction will be very much appreciated, thanks in advanced!







