Google for discrete Video Amplifiersthank you very much
What about the addition of the 43 ohm resistor to the output, do they actually do that in real circuits?
Google for discrete Video Amplifiersthank you very much
What about the addition of the 43 ohm resistor to the output, do they actually do that in real circuits?
Yes they actually do it. It works so well that there is no reason to use anything else.Thank you very much
Still I have a last question:
Is adding a series 43 ohm resistance is the only solution to accomplish the impedance matching?
If not, the only solution, does it the best solution ?
To Jony130, and in all languages I say :Simply you forgot about base current.
http://forum.allaboutcircuits.com/threads/transistor-base.81886/#post-585781
If we assume Hfe = 150 and Vbe= 0.7V then
\(Ie = \frac{Vth - Vbe}{\frac{Rth}{hfe+1}+Re } = 8.22mA\)
So
Ve = Ie * Re = 1.644V
Where
Vth = Vcc * R2/(R1+R2)
Rth = R1||R2
R1 = 10K; R2 = 3.3K