differential amplifier

Thread Starter

electronicsenjoyer089

Joined Feb 24, 2025
182
Hello, i saw the theory behind the differential amplifier and now im building one.

VCC is 12V, VEE = -12V
Itail = 2mA, so ic on each resistor needs to be 1mA.

What i did is first of all calculating the needed resistor in order to have 2mA on R1, so its -VEE-(-VBE)/R1=2*10^(-3) , that does R1=5.65k

now i know that each ic needs to be 1mA and vc needs to be at half of vcc, in order to have maximum swing, so vc is at 6V
so R2=R3 = 6k, is that correct to proceed in this way? what signals i can apply to V3 and V3 before entering in saturation? ( its 6V sine wave or 12V sine wave, similar to vcc value (?).

I got some problems also with my simulation, since when i click on sine generators i got this: ( what u can see in the imagine) how do i fix that? can someone help?

Thanks to everyone.
 

Attachments

ericgibbs

Joined Jan 29, 2010
21,390
hi,
This is plot using 10kHz for V3.
BTW: please assign labels to your test points, it makes it easier to read the plots.
E
EG 1492.png
 

Thread Starter

electronicsenjoyer089

Joined Feb 24, 2025
182
hi,
This is plot using 10kHz for V3.
BTW: please assign labels to your test points, it makes it easier to read the plots.
E
View attachment 349497
now how VD1 and VD2 gonna work? on there i will get the difference beetwen V3 and V4 signals no?, in my case since they are both 2V, if i put myself on vd1-vd2 i will see 0V, but what happens if VD1 is like at 3v? ( what i expect is 3-1, so 2V sine wave? ) another thing that i dont understand is why in this situation if i click on "VD1" node what i see is a sine wave that goes from 6 till down until 5V and the as high as 7V
 

ericgibbs

Joined Jan 29, 2010
21,390
why the sine wave doesnt have the same phase?
hi,
It is a 'Push Pull' amplifier, so the inputs are in antiphase.
Note: you could connect one input to 0V, via a resistor. try that option.

how do i understand whats the max va and vb i can apply?
It depends upon the Gain, you must avoid saturating the Voutput swing.

What do you calculate the Gain to be of the circuit???


E
EG 1494.png
 

Thread Starter

electronicsenjoyer089

Joined Feb 24, 2025
182
hi,
It is a 'Push Pull' amplifier, so the inputs are in antiphase.
Note: you could connect one input to 0V, via a resistor. try that option.



It depends upon the Gain, you must avoid saturating the Voutput swing.

What do you calculate the Gain to be of the circuit???


E
well in this case i have no idea how i can set the gain of the circuit , cus i saw that the relation RC/RE doesnt work properly , so like 6k/5.65k = 1.065, but i saw the gain is much higher

I would like to have a gain of 1 for example, but keeping same parameters, so ie=2mA and ic=1mA
 

Thread Starter

electronicsenjoyer089

Joined Feb 24, 2025
182
hi 089,
Check this Design PDF.
E
Yeah i know that with such design im gonna solve my gain issue, since the current generator has a high internal resistor ( ideally ).

But i didnt get yet how to calculate the gain that i get on each signal ( so on VD1 and VD2 )

beside the design itself, in order to have numbers
 

Thread Starter

electronicsenjoyer089

Joined Feb 24, 2025
182
hi,
The PDF I posted clearly shows how to calculate the Gain.

Is this a Homework or College assignment??

E
View attachment 349507
Yeah, i tried applying this formula to my circuit, but apparently its not true Ad = - RC/RE+ re.

Now i set a RC of 6kOhm and RE is 5.65k so the gain would be around 1,06, but if u apply a signal at va of 1v for example, and extract it on VC u wont see 1,06V , but a lot higher signal, u can check by urself by putting values in the circuit u sent me, thanks.
 
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