I was hoping to figure out how to use loops and kirchoff and calculate the voltages and
Well, maybe this will help youI was hoping to figure out how to use loops and kirchoff and calculate the voltages and
currents that way. Since there is no bias voltage divider, I don't know how to proceed.
Ok. Ic1 = 730μA vs 692μA per LTSWell, maybe this will help you
And for your circuit, if you assumed β1 = β2 = ∞ we have:
Ve2 = Re2*Ic2 = Vbe1+Ic1*Re1 (1)
Vcc = Ic2*Re2 + Vbe2 + Ic1*Rc1 (2)
So we can solve for Ic1:
Ic1 = (Vcc - 2Vbe)/(Re1 + Rc1) = (10V - 1.2V)/(47Ω + 12kΩ) = 730μA
and from there we can find Ic2
Ic2 = Ve2/Re2
Ve2 = Vbe1 + Ic1*Re1 = 0.6V + 730μA*47Ω = 0.634V and Ic2 = 1.92mA
Now we could treat this as our first iteration and in the next iteration, we could include the finite beta value.
What have you expected? By assuming β = ∞ (Ib1 = Ib2 = 0A) I completely ignore the voltage drop across the RB resistor, therefore if we include the base current influence the Ve2 will be:Ok. Ic1 = 730μA vs 692μA per LTS
Ic2 = 1.92mA vs 2.74mA per LTS
Ve2 = 0.634V vs 0.907 per LTS
There is quite a large variance.
LOL. I would expect all that math to give a result that was in the same universe.
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