I assembled a tuning fork with a cd4060 in rc configuration and an lm386. The problem is it heats up, which makes tuning it impossible, as it will change as it heats up. I measured about 160mA, which I thought was a lot for these two chips. I measured the impedance at the power input, ~55ohms. Is there a short, or is this to be expected? Also, I used a mosfet to make the switch a true sp3t (It only connects adjacent pins). This changes the waveform of the two higher octaves (I attached a drawing of the waveform), and the lower octave is quieter than the rest. Is there an easy fix to these?

 

CD4060 is a CMOS logic device. It should not heat up unless you are drawing too much current from an output pin.
If the oscillator frequency is changing then you need to examine the RC components at the oscillator.

 

It is pretty safe to say 160mA indicates a fault somewhere.

Even if the fault is corrected, it will likely not be a successful 'tuning fork' using just an RC frequency base as that can vary unacceptably with ambient temperature, and a crystal timebase is probably called for.

 

Divide and conquer.
First remove the LM386 and measure the current. It should be a couple of milliamps max.
If not, and the CD4060 continues to heat up, you have a defective device

 

That schematic is very hard to interpret. Consider re-drawing it with a more conventional, straight through, left-to-right signal flow. Also, it is not clear which switch terminals are the armatures. There's plenty of room to spread out things for clarity.

ak

 

Start by fixing the problem with excess current - more than likely a short between adjacent strips, I suggest.

Then look at the waveform issue - it is not clear to me what the switch/mosfet connections are - can you explain. If connected as your circuit diagram suggests then I doubt it will work as you intend.

 

Start by fixing the problem with excess current - more than likely a short between adjacent strips, I suggest.

Then look at the waveform issue - it is not clear to me what the switch/mosfet connections are - can you explain. If connected as your circuit diagram suggests then I doubt it will work as you intend.

Pin 2 is the switch's throw, the top 2 positions switch between pins 1 and 3. on the bottom bosition, pin 4 connects the gate to the 4060's pin 6, charging the cap, activating the mosfet, letting the low octave through.

 

Pin 4 connects to O6 on pin 6? Via switch pin1? If O6 is used to switch the mosfet, wont that toggle O8 which is at a lower frequency?

I'm still not clear on the operation of the switch: 1-2, then 2-3, then ? 1-4????

 

A simple question: where did you find this circuit, or did you come up with it yourself?
Can you actually explain its operation? Because I also think that the basic functional assumption is incorrect.

 

YOU DO NOT need that 5volt regulator! It may be oscillating if the capacitors are not close enough. The CD4060 will be quite happy running on 8 or 9 or even on 12 volts.
Fur an instrument tuning source use a crystal to determine the divider input frequency.

(added the next day)
I see also what may be an amplifier, possibly an LM386. Those can draw a fair amount of current if they are driven hard. AND if the voltage regulator is oscillating then the amplifier is being driven hard, AND the V+ is very excessive. I know that from experience MANY years ago.