Hi:

I breadboarded the attached oscillator circuit. The wiring has been checked.
Instead of getting 2Hz out, I get 128Hz. I did not ad the CD4011 yet. Any ideas?

Thanks,
M.

 

Sounds like the oscillator is not running at 32,768Hz.
Check the output at Q4 (pin 7).
It should be 2,048Hz.

 

HI maker,
IIRC the CD4060B oscillator will not run with a 10MHz xtal, with a 5v supply
E

Edit:
Try this 75hct version

 

Sounds like the oscillator is not running at 32,768Hz.
Check the output at Q4 (pin 7).
It should be 2,048Hz.

Hi:
The signal at pin 7 is 2,048 Hz.
M

 

HI maker,
IIRC the CD4060B oscillator will not run with a 10MHz xtal, with a 5v supply
E

Edit:
Try this 74hct version

Hi E:
I am actually running this circuit off of a 32.768Khz crystal for a start.
M

 

The signal at pin 7 is 2,048 Hz.

Then are you sure you are looking at the Q14 (pin 3) out.

 

Hi E:
I am actually running this circuit off of a 32.768Khz crystal for a start.
Thanks,
M

 

I had a "senior moment". I was measuring the signal off of pin14
rather than Q14 (pin 3). However, my scope shows a square wave
but the reading say "f < 10Hz" so I guess that the circuit is likely
putting out 2Hz but the scope maybe doesn't go that low. If that
makes any sense.

M

 

I guess that the circuit is likely
putting out 2Hz but the scope maybe doesn't go that low.

Just do it the old-fashioned way (before digital scopes) and observe/measure the waveform period of one complete cycle, which should be 0.5s.

 

Just do it the old-fashioned way (before digital scopes) and observe/measure the waveform period of one complete cycle, which should be 0.5s.

Unfortunately, I don't know how to do that.

 

Unfortuantely, I don't know how to do that.

A digital oscilloscope likely has a period measurement option.
If not, just set the horizonal sweep to give at least one complete period of the waveform, and then look at how many horizontal divisions that is.
Then multiply the number of divisions by the horizontal sweep speed displayed on the screen, likely in ms (per division).

For example the Rigol scope below is showing an H (horizontal sweep speed) of 20.0µs per division.

 

A digital oscilloscope likely has a period measurement option.
If not, just set the horizonal sweep to give at least one complete period of the waveform, and then look at how many horizontal divisions that is.
Then multiply the number of divisions by the horizontal sweep speed displayed on the screen, likely in ms (per division).

For example the Rigol scope below is showing an H (horizontal sweep speed) of 20.0µs per division.

View attachment 314037

Thanks crutschow. I am learning how to use this new scope. Its been awhile since I was
involved in the hobby. There is a period measurement and it is 500ms.

One last question. Shouldn't the output of the CD4060BE drive a single LED?

 

Shouldn't the output of the CD4060BE drive a single LED?

Depending upon the supply voltage, generally only at low current.
An excerpt below from the data sheet (gasp) shows the available current below:

If you want more LED current, then you can add a transistor buffer.

 

Depending upon the supply voltage, generally only at low current.
An excerpt below from the data sheet (gasp) shows the available current below:

If you want more LED current, then you can add a transistor buffer.

View attachment 314043
View attachment 314042

Thanks!

 

Hi E:
I am actually running this circuit off of a 32.768Khz crystal for a start.
M

That "10M" is the resistor connected across the crystal. The crystal frequency is obvious and to the left of the crystal.