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DC/AC inverter. 12 V to 230 AC with 50 Hz.
The inverter is using unbipolar square puls modulation.
(1) & (2) Gives the harmonics in this equation.
calculation 2: I get negative voltage. Is that possible or am I doing something wrong?
Uh=formula gives you the harmonic components in the figur.
Applied voltage Udinn=12V
Maximum supplied current IN=25A
Internal DC-link voltage ud=?
Supplied voltage Us=230V
Maximum emitted power PN=300W
Interval without supplied voltage u=pi/6
For DC supply to the converter I have:
Voltage U=12V
Maximum load current IN=11.3 A
1) Find the necessary Ud for the given basic harmonic effective value of the square pulse voltage Us=230V, on the assumption that the converter is a full-bridge converter. Us(peak) = sqrt(2)*230= 325.26V. Ud= (pi/4)*Uspeak = 255,47V
2) find the rms value of the 5 most dominant harmonic components in the voltage
Vo1rms= ((4*Ud)/( sqrt(2)*pi*3))*cos(h*(u/2)) -> (4*255.47 / sqrt(2)*pi) *cos(1+(pi/6)/2) = 222V
Vo3rms=54 Vo5rms=11.91 V08rms=-8.5 Vo9rms=-19?
3) calculate THD for a converter with pure (Bipolar) square pulse voltage and the same DC-link voltage.
Thd= sqrt((54^2+11.91^2+8.5^2+19^2)/222^2) =0.266.. What Am I doing wrong? Thanks for the help!
4) Calculate THDu for unibipolar square pulse voltage with u = pi/6
Vorms=Sqrt((pi/6)/pi)*ud=0,4082*Ud
V1rms=(4*Ud)/(sqrt(2)*Pi)*cos((pi/6)/pi)=0.8878*Ud
Thd=sqrt((Vorms/V1rms)^2)=0.46 -> 46%
The inverter is using unbipolar square puls modulation.
(1) & (2) Gives the harmonics in this equation.
calculation 2: I get negative voltage. Is that possible or am I doing something wrong?
Uh=formula gives you the harmonic components in the figur.
Applied voltage Udinn=12V
Maximum supplied current IN=25A
Internal DC-link voltage ud=?
Supplied voltage Us=230V
Maximum emitted power PN=300W
Interval without supplied voltage u=pi/6
For DC supply to the converter I have:
Voltage U=12V
Maximum load current IN=11.3 A
1) Find the necessary Ud for the given basic harmonic effective value of the square pulse voltage Us=230V, on the assumption that the converter is a full-bridge converter. Us(peak) = sqrt(2)*230= 325.26V. Ud= (pi/4)*Uspeak = 255,47V
2) find the rms value of the 5 most dominant harmonic components in the voltage
Vo1rms= ((4*Ud)/( sqrt(2)*pi*3))*cos(h*(u/2)) -> (4*255.47 / sqrt(2)*pi) *cos(1+(pi/6)/2) = 222V
Vo3rms=54 Vo5rms=11.91 V08rms=-8.5 Vo9rms=-19?
3) calculate THD for a converter with pure (Bipolar) square pulse voltage and the same DC-link voltage.
Thd= sqrt((54^2+11.91^2+8.5^2+19^2)/222^2) =0.266.. What Am I doing wrong? Thanks for the help!
4) Calculate THDu for unibipolar square pulse voltage with u = pi/6
Vorms=Sqrt((pi/6)/pi)*ud=0,4082*Ud
V1rms=(4*Ud)/(sqrt(2)*Pi)*cos((pi/6)/pi)=0.8878*Ud
Thd=sqrt((Vorms/V1rms)^2)=0.46 -> 46%
