Can someone help me with part a of this problem?

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crutschow

Joined Mar 14, 2008
38,316
You calculate the voltages for the inputs in their stated states, which seems straight-forward.
What difficulty are you having with that?
Have you not studied Ohm's law and basic circuit analysis?
 

BobTPH

Joined Jun 5, 2013
11,463
Assume one of the inputs V0 or V1 is at ground because that is what is required to make the output low.

How many diodes between V01 and ground? How many between V02 and ground? Does this help you calculate the two voltages?
 

crutschow

Joined Mar 14, 2008
38,316
Why did you not include V1 and V2 in your KVL equations to solve for the node voltages?

Use the value of V1 and V2 to solve for Vo1.
Then solve for Vo2
 

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linhvn

Joined Nov 6, 2024
297
Your equation is wrong. With V1=V2=5V, what is the current in D1/D2 and R?

Why are you using 0.7V for the diode voltage drop when the instructions state it's 0.6V?
Do
Your equation is wrong. With V1=V2=5V, what is the current in D1/D2 and R?

Why are you using 0.7V for the diode voltage drop when the instructions state it's 0.6V?
Your equation is wrong. With V1=V2=5V, what is the current in D1/D2 and R? I cannot solve your answer. I don't know.
 

Thread Starter

linhvn

Joined Nov 6, 2024
297
If the diode is not forward biased, what is its voltage drop?

Hint. You weren't given reverse leakage information for the diode, so I'd assume ideal characteristics for this condition.
that is correct, all diodes are ideal because these are practice problems.
V1, V2 make D1, D2 reverse bias, at D1, D2 open circuit, right?
 

panic mode

Joined Oct 10, 2011
4,864
sigh...

obviously someone needs serious help. the circuit is two separate AND gates.

KVL ass applied in initial post is wrong. it assumes Vf=0.7V even before determining if there is a current through D1 or not.
then results get out of proportion. one should always check if there are any storage elements in the circuit (capacitor or inductor) or additional sources, and if levels are observed at steady state or not. if no storage elements or additional sources, then voltage levels can ONLY be within shown supply limits (0V and 5V). any result outside that range is supposed to be IMMEDIATE red flag.
in other words -0.7V and 5.7V values are a clear signs of wrong analysis.

next one need to observe and analyse individual circuit (gate), not the entire thing. And this better be generic... so it can be applied to the next gate.
 

panic mode

Joined Oct 10, 2011
4,864
in digital world, signals are true or false ( logic 0 / logic 1)
range for levels are defined for each logic family and they are NOT fixed...

so

generic case would be to describe what happens when V1 is at one of the logic levels. simple way to ignore the other input is to connect all inputs together ( V1 =V2).
If V1 is 0V, output Vo1 is _____
If V1 is 5V, output Vo1 is _____
If V1 is undefined (such as 1.785194V), the output Vo1 is ______

this is short and simple and this is what is needed to analyze entire circuit (which could have MANY gatees)
 
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