Where did half of the capacitor charging energy go?
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capeng2.html#c4
When a capacitor is charged from a battery in a DC circuit, half the energy is lost.
QV is the energy from the battery and (1/2)QV is the energy stored on the capacitor.
The other (1/2)QV is lost to resistance.
Question:
If an inductor is placed in series with the capacitor then would (some of the) energy
lost to resistance be instead stored in the inductor and further charge the capacitor
passed (1/2)QV as the capacitor charging current decreased?
As the capacitor charging current decreases, would the inductor respond by becoming
a source in series with the battery, increasing the circuit voltage to resist the decreasing
capacitor charging current?
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capeng2.html#c4
When a capacitor is charged from a battery in a DC circuit, half the energy is lost.
QV is the energy from the battery and (1/2)QV is the energy stored on the capacitor.
The other (1/2)QV is lost to resistance.
Question:
If an inductor is placed in series with the capacitor then would (some of the) energy
lost to resistance be instead stored in the inductor and further charge the capacitor
passed (1/2)QV as the capacitor charging current decreased?
As the capacitor charging current decreases, would the inductor respond by becoming
a source in series with the battery, increasing the circuit voltage to resist the decreasing
capacitor charging current?