Hi everyone...
I need to calculate the Ic for the attached circuit, using Thevenin method!
β=167.1
Vcc = 20V
R1 = 160kΩ
R2 = 40kΩ
Re = 1kΩ
I'm calculating Vth = (40/(40+160))*20 = 4V
Then Rth = (160*40)/(160+40)=3.2kΩ
Then using input net (base net) I'm calculating Ib as:
Ib = (Vth - Vbe)/(Rth + Re(β+1)) = (4-0.7)/(3.5k+1k*(167.1+1))=19.26μA
Then using Ic = β*Ib = 167.1*19.26μA = 3.22mA but the correct result is 2.75mA... Can't figure out where am I going wrong!
I need to calculate the Ic for the attached circuit, using Thevenin method!
β=167.1
Vcc = 20V
R1 = 160kΩ
R2 = 40kΩ
Re = 1kΩ
I'm calculating Vth = (40/(40+160))*20 = 4V
Then Rth = (160*40)/(160+40)=3.2kΩ
Then using input net (base net) I'm calculating Ib as:
Ib = (Vth - Vbe)/(Rth + Re(β+1)) = (4-0.7)/(3.5k+1k*(167.1+1))=19.26μA
Then using Ic = β*Ib = 167.1*19.26μA = 3.22mA but the correct result is 2.75mA... Can't figure out where am I going wrong!
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