Whether you model them as current-controlled or voltage-controlled depends on the model you use which depends on what is most appropriate for your circuit. It also depends on whether you are talking about large signal or small signal behavior.Hey,
So I need to analyze a few designs that include BJTs, but all of my textbooks only cover MOSFET analysis. Can I model the BJTs as dependent sources (current-controlled)? How can I approach this?
Sorry, I'm using them for a switching application. Could I assume them either saturated or in the active region and then use their β-α characteristics for the current/voltage?Whether you model them as current-controlled or voltage-controlled depends on the model you use which depends on what is most appropriate for your circuit. It also depends on whether you are talking about large signal or small signal behavior.
If you are using them for a switching application, then you want them to either be saturated or off. You want to keep them out of the active region except during the brief transient switching times.Sorry, I'm using them for a switching application. Could I assume them either saturated or in the active region and then use their β-α characteristics for the current/voltage?
Your circuit won't do that. But it is not too far off.Behvavior...right! You might need that.
So when SW is open, Q1 should be driven saturated which should cause C to charge through R5. When SW is closed, Q1 should be grounded and turned off while Q2 is driven, causing C to discharge through R4.
Nope.OK, I feel pretty dumb. I feel like I'm looking right at the problem...
Does it have anything to do with R4 being connected to the collector?
I can't imagine this thing working if I leave the RC branch where it is. When the switch opens, the voltage on R5 will go to Vcc which will charge the cap....Now think of what you want for the charging path. You want a path the goes from the capacitor through R4 and then through Q2 to the positive supply rail (VCC).
I don't know what you are referring to by "the RC branch" since you have two Rs. With the current circuit, when switch is open Q2 will turn on taking the top of R5 to Vcc. But the other end of R5 will be open and no current will flow through it. The cap will then charge through R4. Notice that R5 is NOT involved in the charging process. Why is that? You want the same thing to be the case for R4 during the discharging process so that it is NOT involved in the discharging process.I can't imagine this thing working if I leave the RC branch where it is. When the switch opens, the voltage on R5 will go to Vcc which will charge the cap.