What happens to the behavior of fully-charged inductor and capacitor elements when they are switched into a circuit with a new source?
The circuit I am curious about involves two resistors in series with a 2A current source and an inductor. There is also a capacitor in parallel with one of the resistors. After a long time, a switch connecting the 2A source changes to a 9V source, effectively replacing sources.
I know that in the original circuit with the current source, the inductor is charged to 2A and acts as a short, while the capacitor acts as open. Right after the switch is made, does the inductor continue acting as a short for that instant with a 2A current flowing through it? And does the capacitor in that moment still act as an open circuit, with an open circuit voltage of however many volts it had right before the switch? I'm inclined to believe so, but I wanted to verify.
The circuit I am curious about involves two resistors in series with a 2A current source and an inductor. There is also a capacitor in parallel with one of the resistors. After a long time, a switch connecting the 2A source changes to a 9V source, effectively replacing sources.
I know that in the original circuit with the current source, the inductor is charged to 2A and acts as a short, while the capacitor acts as open. Right after the switch is made, does the inductor continue acting as a short for that instant with a 2A current flowing through it? And does the capacitor in that moment still act as an open circuit, with an open circuit voltage of however many volts it had right before the switch? I'm inclined to believe so, but I wanted to verify.