Q. Inductor coil takes a current of 2A from a 12V dc supply.
When connected to 240V, 50Hz supply the current is 20A
Resistance ?
Impedance ?
Inductive Reactance?
Indutance of coil?
Ive been using the techniques shown in this sites tutorial.
R = 12V / 2A
Z = 240V / 20A
Since Z = R + XL
Rearranging:
XL = Z - R
= (12ohms at -90deg. (polar notation)) - (6ohms at 0deg.)
= 13.4ohms
The correct answer is 10.39ohms.
Where am I going wrong?
Thanks
When connected to 240V, 50Hz supply the current is 20A
Resistance ?
Impedance ?
Inductive Reactance?
Indutance of coil?
Ive been using the techniques shown in this sites tutorial.
R = 12V / 2A
Z = 240V / 20A
Since Z = R + XL
Rearranging:
XL = Z - R
= (12ohms at -90deg. (polar notation)) - (6ohms at 0deg.)
= 13.4ohms
The correct answer is 10.39ohms.
Where am I going wrong?
Thanks