Hi,
I have stumbled on some analog filter design calculation that puzzles me. We have a transfer function
\[ T(s) = \frac{|1+jw/z|}{|1 + jw/p|} \]
next author says that we can express the magnitude response as:
\[ \alpha = 20log{|1+jw/z|} - 20log{|1 + jw/p|} \]
Next he wants to focus just one the first log of the above formula and says that for a high frequency this can be simplified to:
\[ \alpha = 20log(\sqrt{1 + \frac{w}{z}^2)} = 20 log(w/z) \]
So far this is clear, but the he says, IF we rase the frequency by 10 then \[ \alpha = 20log(10w/z) = 20log(10) + 20log(w/z) = 20 + \alpha_2(w) \]
and he concludes "Thus for an increase of frequency by a factor of 10 the attenuation increased by 20db. Why attenuation? We got +20 not -20, second this part was a numerator of a transfer function so every increase in there should cause an increase in the system response not a decrease. Is it a mistake or I miss something?
Thanks!
I have stumbled on some analog filter design calculation that puzzles me. We have a transfer function
\[ T(s) = \frac{|1+jw/z|}{|1 + jw/p|} \]
next author says that we can express the magnitude response as:
\[ \alpha = 20log{|1+jw/z|} - 20log{|1 + jw/p|} \]
Next he wants to focus just one the first log of the above formula and says that for a high frequency this can be simplified to:
\[ \alpha = 20log(\sqrt{1 + \frac{w}{z}^2)} = 20 log(w/z) \]
So far this is clear, but the he says, IF we rase the frequency by 10 then \[ \alpha = 20log(10w/z) = 20log(10) + 20log(w/z) = 20 + \alpha_2(w) \]
and he concludes "Thus for an increase of frequency by a factor of 10 the attenuation increased by 20db. Why attenuation? We got +20 not -20, second this part was a numerator of a transfer function so every increase in there should cause an increase in the system response not a decrease. Is it a mistake or I miss something?
Thanks!