I've never said there are not sources and currents in the generator equation (or in electromagnetics in general) so your question is a classic strawman (and sort of disappointing as a poor strawman). I merely state the obvious, they are not the carriers of electrical energy.So here's a challenge for you (and I would legitimately like to see the result).
Imagine two generators (we can make it as simple as a single loop of wire turning in a static magnetic field). In one generator, the wire is made of copper, but in the other generator it is made of glass. Since it is all about the fields and not about the movement of charge carriers and the net charge carrier movement is zero here (since this is going to be an AC generator), explain, in terms of the fields only, why we get power from one and not the other. Remember, no mention of any motion of charge carriers is allowed, everything must be described in terms of the fields.
A classic electron kinetic energy calculation for a circuit current.
That electron KE represents a possible loss of electrical energy in the circuit.A 2 mm wire carrying a 1 Amp current has electron drift velocities around 2.5E-5 meters/second, so at 1/2 mv^2, each electron has a staggering 2.38E-40 joules of kinetic energy. Suppose the voltage is 1 V, so 1 Amp of current is carrying 1 joule per second of energy. At the same time, the coulomb of electrons is (6.2E18) is carrying 1.4E-21 joules of kinetic energy.
They (charge carriers) are a vital part of the energy conversion process because they have the property of electric fields.
Using QFT it's possible to use the “electron field” and the electromagnetic field for your generator question but that's pretty esoteric.
In quantum field theory, what we perceive as particles are excitations of the quantum field itself.
With those two QM fields it's possible to make a hand-waving explanation of a generator but of course, your strawman two generation setup won't work (as I'm sure you already know) even with QFT.
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