A lot of issues with this approach. If the decharging time is longer than the charging time, then pulses will get stretched. Also, there is a limit to how much the capacitor can be charged to, which means that pulses that would need to exceed that voltage will all end up being the same length. On top of that, how do you discharge the capacitor for pulses that are too short to reach your triggering threshold?If your pulse is always with the same amplitude, you can make a circuit, which charges a capacitor with triggering this signal, and the circuit will de-charge the capacitor in longer time than charging. The more pulse width, the more charging of capacitor. Then you can calculate the discharge time (or maximum charged voltage of capacitor) that related to pulse width.
The output pulses must be stretched to be within the our measurement range.If the decharging time is longer than the charging time, then pulses will get stretched
The capacitor is not connected to the pulse directly and located on the output side of the circuit. This output side has different discharge time constant with it's resistor that we can set it to desire value.how do you discharge the capacitor for pulses that are too short to reach your triggering threshold?
by Aaron Carman
by Jake Hertz
by Duane Benson
by Duane Benson