Decrease value of resistor R5.However when I attached the circuit with transistors and resistors and then measure the votlage V1 as follows then I get 1.343VDC instead of 3.182VDC. Why is that and how I can resolve to get 3.182VDC?
It's up to you.I shouldn't have to decrease resistor value
I dont get it why? Zener diode breakdown voltage is 3.12V. If zener diode is reversed biased and breakdown without attaching the circuit with transistor why would it change when attaching circuit with resistor? I shouldn't have to decrease resistor valueDecrease value of resistor R5.
R4 is actually the loadWhy is R4 1Ω?
Change R4 to a higher value, say 1000Ω, and see what happens.
It's because you are insisting on using a zero-order model of a zener diode. Where are you getting the magical value of 3.12 V in the first place? Your model name implies that it is a 3.0 V zener. Be that as it may, like any diode of any kind, the voltage drop across it is a function of many parameters, including primarily the current flowing through it and the temperature. Change either of those, and you change voltage across it. When you add the additional components to your circuit, some of the current in the 600 Ω resistor that used to go through the zener goes elsewhere, so less current is flowing in the zener and the voltage across it changes.I dont get it why? Zener diode breakdown voltage is 3.12V. If zener diode is reversed biased and breakdown without attaching the circuit with transistor why would it change when attaching circuit with resistor? I shouldn't have to decrease resistor value
i dont follow??What happens when you have a 600Ω source feeding a 1Ω load?
So then what can be done to correct the situation?You cannot use KVL or KCL to analyze the circuit because you don't know the transfer function at the MOSFET.
Q1 is turned off. The voltage on the gate of the MOSFET tries to rise. The MOSFET tries to conduct and pulls V1 down.
Hence you have a negative feedback that settles at V1 = 1.34V.
Disconnect R4 and see what happens.So then what can be done to correct the situation?
R4 is my load. Then where i put my load?Disconnect R4 and see what happens.
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.What is the "correct" situation?So then what can be done to correct the situation?
And what is it that you are trying to do with (or to) this 1 Ω load?R4 is my load. Then where i put my load?
Two transistors together are switch which turn off light load R4 when the V2 voltage is 0.5vdc or above and turn on when v2 is below 0.5vdc.What is the "correct" situation?
Unless I missed it (which is possible), you've given no indication of what the problem is that you are trying to solve. What it is that you are trying to accomplish. What the purpose is of this circuit.
And what is it that you are trying to do with (or to) this 1 Ω load?
R4 is 3V/0.2A = 15 Ohms, not "little larger than 1 ohm". Why don't you just use a 3.3V regulator instead!Two transistors together are switch which turn off light load R4 when the V2 voltage is 0.5vdc or above and turn on when v2 is below 0.5vdc.
I am trying to get zener diode series resistor so that i can get stable 3.1V supply since my voltage source v1 varies from 3v to 12v.
my load R4 is light that takes 200mA at 3VDc so R4 is little larger than 1 ohms.
my problem is when i attach zener didoe series resistance to the circuit with transistors and when V2 is at or below 0.5vdc i dont get 3.1V voltage at zener diode. How can I correct this situation to get 3.1V?