I've seen in Sedra&Smith or here that the collector of a NPN-BJT is much bigger than the emitter why is that so?
The only thing what comes in my mind about it, is that when forward biased the base-collector "diode" has a lower voltage drop compared to the base-emitter "diode" given the same current.
On the other hand when we would make it the opposite, e.g. emitter bigger than collector the bjt would be better suited as a switch no? Since we could have $v_{ve} = 0$ and still $v_C/v_E > 0$.
Of course bjt's are not always a used as switch's, but are are my calculations correct in essence?
PS: This is my first question, is there something like math jax? Any math formatting tools?
The only thing what comes in my mind about it, is that when forward biased the base-collector "diode" has a lower voltage drop compared to the base-emitter "diode" given the same current.
On the other hand when we would make it the opposite, e.g. emitter bigger than collector the bjt would be better suited as a switch no? Since we could have $v_{ve} = 0$ and still $v_C/v_E > 0$.
Of course bjt's are not always a used as switch's, but are are my calculations correct in essence?
PS: This is my first question, is there something like math jax? Any math formatting tools?