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Common Emitter AmplifierView attachment 351036
How should I approach the question with a solution? I don't have much of an idea, I need it urgently. Assume RL resistance is 20k
It states Vcc = 15 VWhat is the voltage level for -Vcc?
Or is it something else that you are required to determine?
Oh, I was about to suggest 0V !!It states Vcc = 15 V
Hence, one must assume +Vcc = +15 V, -Vcc = -15 V
Why would I do that when the problem states 10K?Assume RL resistance is 20k
It would be difficult to get a 24Vpp output with a 15V supply differential.Oh, I was about to suggest 0V !!
The you need to go back into your text (or other material) and get some idea this time around (revisiting concepts that didn't gel the first - or nth - time is part of the learning process, particularly in technical subjects).View attachment 351036
How should I approach the question with a solution? I don't have much of an idea, I need it urgently. Assume RL resistance is 20k
I think it means the AC pass band starts at 10Hz, so just DC blocking.I wonder what the point of designing it for 10Hz cutoff it it's going to have a high-pass frequency of 20kHz?
I think that it probably meant to say that the "high frequency cutoff" isI wonder what the point of designing it for 10Hz cutoff it it's going to have a high-pass frequency of 20kHz?
I took it as audible range 10Hz to 20Khz, not that it changes the approachI think that it probably meant to say that the "high frequency cutoff" is 10 kHz.
The 10 kHz was a typo on my part.I took it as audible range 10Hz to 20Khz, not that it changes the approach![]()
How much confidence can you have in the course if whoever is writing the assignment makes such a basic error?We know what the writer of the assignment meant. It is simply worded with the opposite of what was intended.
It should have said low pass filter with cutoff frequency at 20 kHz.