And if we do this, we see that Early's voltage (VAF) has a very low-value VAF = 10V. Thus, the transistor output resistance (ro) will be extremely low..MODEL 2N2222_Multisim npn

+IS=1.87573e-15 BF=153.575 NF=0.897646 VAF=10

+IKF=0.410821 ISE=3.0484e-09 NE=4 BR=0.1

+NR=1.00903 VAR=1.92063 IKR=4.10821 ISC=1.94183e-12

+NC=3.92423 RB=8.70248 IRB=0.1 RBM=0.1

+RE=0.111394 RC=0.556972 XTB=1.76761 XTI=1

+EG=1.05 CJE=1.67272e-11 VJE=0.83191 MJE=0.23

+TF=3.573e-10 XTF=0.941617 VTF=9.22508 ITF=0.0107017

+CJC=9.98785e-12 VJC=0.760687 MJC=0.345235 XCJC=0.9

+FC=0.49264 CJS=0 VJS=0.75 MJS=0.5

+TR=3.55487e-06 PTF=0 KF=0 AF=1

**ro ≈ (11.3V + 10V)/3.73mA ≈ 5.7kΩ**

Therefore the voltage gain will be around

**Av ≈ (Rc||RL||ro)/re ≈ (5kΩ||5.7kΩ||100kΩ)/6.9Ω ≈ 2.6kΩ/6.9Ω ≈ 376V/V**