Put it across the output of the variac, and increase the voltage from zero until the current = 0.75A. Measure the voltage.Yes I had the idea actually. XL=2*pi*F*L and V=I*XL
feed 220v. measure the current while playing with F.
make a few points and get the average. right?
The odds are that 0.75A is a thermal limit. If you exceed that, it will get too hot.Yes I understand that. I have a different question now:
What happens if I inject more than 0.75A?
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