Voltage Multiplier

Brownout

Joined Jan 10, 2012
2,390
Here are the following equations that I computed awhile ago

logarithmic:
Vo1 = -Vtln(V1/Is*R1)
Vo2 = -Vtln(V2/Is*R2)

summing:
Vo' = Vtln(V1*V2/Is^2*R^2)

where R = R1*R2 since these two resistors are equal. I evaluated them as one giving us R^2.

anti-log:
Vo = -Rf(V1*V2/Is*R^2)

inverting:
Vo = -Rf/Ra (-Rf*V1*V2/Is*R^2)
There is a mistake in your last eqn. The inverting state is a unity gain, the gain is -Rf/Rin = -1k/1k = -1. Yet you introduce an Ra factor in your last eqn, where the last stage should only be -v(antilog)
 
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