I tested the following circuit .... The problem is it doesn't switch off it remains on ON state .....wat is the problem
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Am using a 50KHz signal ....by the way it is a buck converterA normal high-side driver isn't going to work unless it is switching at more than a few tens of Hz.
I presume that this circuit doesn't switch very often, so would need one with a separate charge pump.
How about switching the negative side?
Yes, I saw that. Here's the problem:This is the circuit am using
Had first connected the Mosfet in that way (vice versing the drain and source terminals) but the voltage at the source will be 0V so will be the one at the gate so it will remain at off stateHi,
There is an internal diode in the MOSFET.
E
Meaning that if solar voltage is 20V then gate voltage should be around (28-30).....Sir please explain am not understanding what you sayingYes, I saw that. Here's the problem:
View attachment 226459
There is a diode between "S" and "D" that is forward biased. It will not turn off, regardless of the gate voltage. If you reverse those connections, then the mosfet will be off and can be turned on with a gate voltage about 8V to 10V GREATER than the solar voltage.
Isn't 50kHz a bit of a challenge for a PC817?Am using a 50KHz signal ....by the way it is a buck converter
I think it can handle thatIsn't 50kHz a bit of a challenge for a PC817?
Rise time for 1k load = 20us. Fall time for 1k load = 20us. That's already 40us. You're much more optimistic than I am!I think it can handle that
by Jake Hertz
by Jeff Child
by Jake Hertz