I am working on 1 D from the homework attached. I have found Vce to be -0.5V.
I found this knowing Vout=Vcc-(Bf)(Rc)((Vi-VBEon)/Rb)
=5-(100)(2k)((1.25-.7)/20k)
=5-5.5
=-.5
I am guessing the transistor is operating in the Reverse Active Region.
My instructor said to "Switch the C & E Terminals and Bf->Br"
Can someone explain what my instructor is trying to say by this??
Thanks
Daniel
Cal Poly Pomona
I found this knowing Vout=Vcc-(Bf)(Rc)((Vi-VBEon)/Rb)
=5-(100)(2k)((1.25-.7)/20k)
=5-5.5
=-.5
I am guessing the transistor is operating in the Reverse Active Region.
My instructor said to "Switch the C & E Terminals and Bf->Br"
Can someone explain what my instructor is trying to say by this??
Thanks
Daniel
Cal Poly Pomona
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