Transistor Base Current Help

Thread Starter

Ndjs

Joined Sep 26, 2012
18
Hi guys,

I am new to this forum and starting to play around with electronics.

I have a question about BC547 Transistors.

Using the following data sheet

http://www.futurlec.com/Transistors/BC547.shtml

Using a 9 V DC supply and the Emitter tied to ground and the collector having a RED LED and a resistor in series with Vcc.

Would I be able to turn the led off if I had a big enough Potentiometer? I have tried 100K pot and it dims it only not turning it completely off. So I am guessing the answer is yes.

My main question is what current do I need the base to be for the transistor to be open? And where does it indicate this on the data sheet.
 

ramancini8

Joined Jul 18, 2012
473
Please supply a circuit schematic. Zero base current means zero collector current and an LED in the collector circuit is off. Sufficient base current turns the transistor and LED on.
 

Markd77

Joined Sep 7, 2009
2,806
If you connect the two ends of the pot to ground and Vcc and the centre to the base it is possible to turn it off completely.
 

crutschow

Joined Mar 14, 2008
38,936
If you connect the two ends of the pot to ground and Vcc and the centre to the base it is possible to turn it off completely.
Make sure you have some resistance in series with the base, otherwise you can zap the transistor when the pot is at the top of its setting.
 

Thread Starter

Ndjs

Joined Sep 26, 2012
18
Thankyou for your posts

There has to be a cut off point where there is not enough current to turn the transistor on. If I put a 2megohm resistor in series with the base the LED turns off.

Does that mean the transistor has turned off ?..

If this is a 9 V supply The current in the base = 9/10^6 = 4.5x10^-6 (4.5uA)

Or do we just say that IB (No current in base) the transistor does not switch.

I guess my main point Do we know what current when applied to the base will switche the transistor
 

Audioguru

Joined Dec 20, 2007
11,248
A transistor is a linear amplifier if it has plenty of collector to emitter voltage so it is not a saturated switch. Then its collector current is hFE x base current. hFE is a range of numbers because each transistor is different and temperature also changes hFE.

But you want the transistor to be a saturated switch with an extremely low collector to emitter voltage so hFE cannot be used in the calculation.
The datasheet for nearly every transistor shows that it works very well as a saturated switch when its collector current is 10 times its base current.
 
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